Question about Sony Xplod XM-1652Z Car Audio Amplifier

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HOW DO I BRIDGE MY DUAL VOICE 4OM TO 2OM

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Tie both "+" terminals together and then both "-" terminals together. That puts the voice coils in parallel, making the combination a total of 2 ohms.

Posted on Dec 08, 2008

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Bridge 2 10's to a 2channel amp


most times it is L+ and R-. If the amp is bridegable. Also, make sure you don't go to low in the ohms. If your amp only runs at 4 ohms mono. Don't bridge it down o 2 ohms mono. If you have dual voice coil subs. bridge the coils of the subs in series, then bridge the two subs outside the box parallel.

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I need help hooking my kicker cvr 12 to my direct 600 amp


Is the sub a single voice coil or dual???? If its a single, just bridge sub to amp....(+ of one channel and the - of the other) amp should show where to bridge with a diagram near speaker outs. If its a dual voice coil, then run one voice coil to the left channel and one voice coil to the right.

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I have 2 Maaudio HK4000 and i whant to bridge toghater? i have 2 pioneer subwoofers and i have it come down in 2ohm thogater. How can i bridge it?? mvh Leif


What are the ohms of the subs? Are they single or dual voice coils??? But FYI you can bridge the amps together, You have to use them separate one sub on each one. You can't run one sub on 2 amps.

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Orion hcca 250 digital reference & orion XTR 12" 500w dual subs


If you have one sub dual voice coil, just paralel the sub and conect to brigde amp. Simple...

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Ok, I have a pair of infinity dual voice coil 12" subs, and a pair of audiobahn quad voice coil 12" subs. Boths sets of speakers can handle 450w. Which set of 12's would be best to hook up to this amp, and...


i recomend you just use the best single woofer in a well built box and that will give you better sound at lower gain volumes it sounds like you have too much junk laying around but to get good bass run your sub at 2 ohms if the amp is stable at that impedence

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1 Answer

Bridging 800a4


That all depends upon whether or not the sub you are running has dual voice coils or just a single voice coil. The 800a4 is a four channel amp; thus the only way you can bridge it will be 3 channel or 2 channel. If you are running a dual voice coil sub then you can wire the amp two channel and get 400 watts x 2 @ 4 ohms. Make sure that you sub can handle this kind of power though.

Here are the specs:
4 x 100 @ 4 ohms (13.8V - <0.05% THD)
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Fuse: External 60A
Manufactured in 1999 - 2001

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1 Answer

Prsx720


The specs I read on the Pioneer site say the amp is not 1 ohm stable, so keep that in mind.

It partially depends on the impedance of each voice coil on the DVC subs. If they are dual 4 ohm, and you connect the DVCs in parallel ("+"s together, "-"s together), you could run a sub on each channel of the amp(s). This would put about 200W on each sub.

The other option is to still tie the dual 4 ohm voice coils in parallel, tie 2 subs in series (one "+" to the other "-"), and bridge the two channels of the amp (aka put them in parallel). But this, also, would be about 200W on each sub.

Things get different if the subs have dual 2 ohm, 3 ohm, or 8 ohm voice coils.

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1 Answer

Subs


2x12 in sub each duel voice coil can iether wire to 1 or 4 ohms. im guessing you have everything wired up in series (1 ohm) and aer probably burning out the amp.

http://www.crutchfield.com/learningcenter/car/subwoofers_wiring.html?imageID=2DVC%5F4%2Dohm%5Fmono

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1 Answer

Amp Problems


You are probably presenting too low an impedance load to the amplifier. In bridged mode the amp must be connected to a minimum 4-ohm load. If your subwoofer is a dual voice coil type with 4-ohm voice coils, you cannot wire the voice coils in parallel and connect it to the bridged amplifier. If you have a sub with dual 2-ohm voice coils, you can wire the voice coils in series and connect it to the amplifier in bridged mode. To connect voice coils in series: Connect a wire from the negative terminal of one coil to the positive terminal on the other coil. Connect the unused positive and negative terminals to the amplifier's output.

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