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Posted on Jan 02, 2017

What you want to do is solve the linear equation 2x=10 to find the value of the unknown x that makes the equality true. Solving an equation usually involves rearranging therms, factors and so on. However your calculator was not designed to handle the solution of equations, no matter how simple they are.

Some Casio scientific calculators can solve some types of equations (polynomials of degree 2 or 3, simultaneous linear equations in up to 3 unknowns). These are the FX-115 ES (Plus) and FX-991 ES (Plus C). Other equivalent models are sold in the world under different names.

Some Casio scientific calculators can solve some types of equations (polynomials of degree 2 or 3, simultaneous linear equations in up to 3 unknowns). These are the FX-115 ES (Plus) and FX-991 ES (Plus C). Other equivalent models are sold in the world under different names.

Oct 16, 2013 | Casio FX350MS Scientific Calculator

This calculator is unable to factor a polynomial expression.

In general there are a few factoring methods

In general there are a few factoring methods

**Factor by grouping terms****Factor by completing the square**(quadratic polynomial)**Factor by finding two integers such their sum is equal to the coefficient of the middle term, and their product is equal to the third (constant term)**. This is valid for a quadratic polynomial where the leading coefficient (of the x^2 term) is equal to 1.**X^2+SX+P**

Jul 31, 2012 | Casio FX-115ES Scientific Calculator

I believe some minimal amount of knowledge of the concept will go a long way to teach you any subject.

When you say solve in Math, you mean solve an equation. An equation is a mathematical expression (with some unknown) that is equal to some other expression, usually a known value. That requires an = sign. However you do not have one.

All you can do is write the expression in as compact a form as possible. In this case, you combine the two like-terms that have the variable n to get 3n.

You expression is therefore 3n-3000. Period.

When you say solve in Math, you mean solve an equation. An equation is a mathematical expression (with some unknown) that is equal to some other expression, usually a known value. That requires an = sign. However you do not have one.

All you can do is write the expression in as compact a form as possible. In this case, you combine the two like-terms that have the variable n to get 3n.

You expression is therefore 3n-3000. Period.

Jan 12, 2012 | SoftMath Algebrator - Algebra Homework...

Do you really need a calculator to solve a linear equation?

Let us see how to solve it without a calculator.

Remove the parentheses fronm the second term on the left : y-3

Use the distributive property on the last term on the right side -2y-6

Take the term -3 to the right side, changing its sign in the process (becomes +3)

Take the -2y term to the left making it +2y.

3y +2y=18+3-6 or 5y=15 and the answer is straightforward .

As to your Casio FX300ES, it cannot solve equations because it does not have an EQUATION calculation mode. The Casios FX-115ES and FX-991ES have an Equation Mode. If you use any of the two to solve an equation in one variable (linear, quadratic or other) the unknown is taken to be x by default. You would have to change the name of the variable from y to x.

Let us see how to solve it without a calculator.

Remove the parentheses fronm the second term on the left : y-3

Use the distributive property on the last term on the right side -2y-6

Take the term -3 to the right side, changing its sign in the process (becomes +3)

Take the -2y term to the left making it +2y.

3y +2y=18+3-6 or 5y=15 and the answer is straightforward .

As to your Casio FX300ES, it cannot solve equations because it does not have an EQUATION calculation mode. The Casios FX-115ES and FX-991ES have an Equation Mode. If you use any of the two to solve an equation in one variable (linear, quadratic or other) the unknown is taken to be x by default. You would have to change the name of the variable from y to x.

Sep 08, 2011 | Casio fx-300ES Calculator

The calculator does not have an equation SOLVER. But to solve this equation or any linear equation you need no calculator. Use the properties of equalities to isolate the unknown.

X-17=34

X-17**+17**=34+**17** (Adding the same number to both sides of an equality does not break the balance).

Since -17+17=0 and 34+17=51

You get X=51

X-17=34

X-17

Since -17+17=0 and 34+17=51

You get X=51

Aug 21, 2011 | Casio fx-300ES Calculator

You enter the problem into the calculator and when you are finished you press the equals sign to make it give you the answer to your problem.

Here is an example;

If I wanted to know what the sum (or total) was for 2 + 10+ 16 - I would enter the number 2 and then the plus sign + and then the number ten and the plus sign + and then the number sixteen and the plus sign again + and then press the equals sign which looks like this =. when I press the equals sign = the calculator gives me the answer to my question of what the total of those numbers are.

I hope this helps?

Here is an example;

If I wanted to know what the sum (or total) was for 2 + 10+ 16 - I would enter the number 2 and then the plus sign + and then the number ten and the plus sign + and then the number sixteen and the plus sign again + and then press the equals sign which looks like this =. when I press the equals sign = the calculator gives me the answer to my question of what the total of those numbers are.

I hope this helps?

Jul 16, 2011 | Casio fx-300ES Calculator

You are looking for a line (y=m*x+b) and have two points. From this information you can generate two equations with two unknowns (m and b are unknown).

First plug in the first point (1,5) to the general form:

5(the y value of the point) = m*1(the x-value at this point)+b

Do the same for the second point you're given.

From here solve the first equation for m in terms of b.

Plug this value of 'm' into the second equation so you will end up with something like:

3=(something in terms of b)*(-2)+b

This final equation can be solved for b (try factoring)

You now have a value for the y-intercept. Plug that into y=m*x+b

Choose either of the two points, plug into the equation on the last line with the value of b known

You then know y, x, and b and have m as the remaining 1 unknown. Solve for that and put it all together for your final answer.

First plug in the first point (1,5) to the general form:

5(the y value of the point) = m*1(the x-value at this point)+b

Do the same for the second point you're given.

From here solve the first equation for m in terms of b.

Plug this value of 'm' into the second equation so you will end up with something like:

3=(something in terms of b)*(-2)+b

This final equation can be solved for b (try factoring)

You now have a value for the y-intercept. Plug that into y=m*x+b

Choose either of the two points, plug into the equation on the last line with the value of b known

You then know y, x, and b and have m as the remaining 1 unknown. Solve for that and put it all together for your final answer.

Apr 23, 2011 | Texas Instruments TI-83 Plus Calculator

I am afraid you cannot use the TI8xPlus family of calculators to solve linear systems in matrix form. In this calculator, matrices must have real coefficients.

You can however separate (expand) the problem into a linear system of 4 equations in 4 unknowns and try to solve it with the calculator.

If I did not make mistakes during the expansions and the gathering of terms you should get the following equation

-(8a+8c+10d) +i*(-8b+10c-8d) =0+i*0 from which you extract an equation for the real parts, -(8a+8c+10d)=0 and another for the imaginagy parts i*(-8b+10c-8d) =i*0

If I did not make mistakes (you should be able to find them, if any) your system of two linear equations with complex coefficents has been converted to a system of 4 linear equations with real coefficients.

8a-15b-8c=10

15a+8b-8d=0

8a+8c+10d=0

-8b+10c-8d =0

Now, you can in theory solve this system with help of the calculator, to find a, b, c, and d. When these are found, you can reconstruct the X and Y solutions.

Now get to work: Ascertain that my extracted equations are correct, then solve for a, b,c, and d, and reconstruct X and Y.

I am no seer, but my hunch is that this system is degenarate. I will not explain what that means.

You can however separate (expand) the problem into a linear system of 4 equations in 4 unknowns and try to solve it with the calculator.

- define X = a+i*b
- Define Y=c+i*d
- Rewrite the first equation substituting a+i*b for X and c+i*d for y.
- Gather all real terms together, and all imaginary terms together on the left.
- You will have (8a-15b-8c) +i(15a+8b-8d) = 10 +0i
- This equation can be split into two equations by saying that

- the real part pf the left member is equal to the real part of the right member, this gives 8a-15b-8c=10, and
- the imaginary part of the left member is equal to the imaginary part of the right member, this gives 15a+8b-8d=0

If I did not make mistakes during the expansions and the gathering of terms you should get the following equation

-(8a+8c+10d) +i*(-8b+10c-8d) =0+i*0 from which you extract an equation for the real parts, -(8a+8c+10d)=0 and another for the imaginagy parts i*(-8b+10c-8d) =i*0

If I did not make mistakes (you should be able to find them, if any) your system of two linear equations with complex coefficents has been converted to a system of 4 linear equations with real coefficients.

8a-15b-8c=10

15a+8b-8d=0

8a+8c+10d=0

-8b+10c-8d =0

Now, you can in theory solve this system with help of the calculator, to find a, b, c, and d. When these are found, you can reconstruct the X and Y solutions.

Now get to work: Ascertain that my extracted equations are correct, then solve for a, b,c, and d, and reconstruct X and Y.

I am no seer, but my hunch is that this system is degenarate. I will not explain what that means.

Feb 10, 2010 | Texas Instruments TI-84 Plus Calculator

Hi,

First let us repair the terminology.

Hope it helps.

Thank you for using FixYa and for rating this solution.

First let us repair the terminology.

- You can evaluate any expression (find the value of any expression for a particular value of its variable).Store a value in the variable, say X. Key in the expression and press [EXE].
- You can consider your expression(should not contain a relational operator such as =, greater than, less than, greater than or equal to, less than or equal to) to be a function Y1(x) = expression and graph it, or generate a table for it. You will have several values of the function calculated at various points.
- You can set your expression equal to 0 and find the particular value(s) of the variable (the unknown) that make the equality TRUE. That is called solving an equation.

Hope it helps.

Thank you for using FixYa and for rating this solution.

Nov 05, 2009 | Casio FX-7400G Plus Calculator

A positive number is 5 times another number.If 21 is added to both the numbers,then one of the new numbers becomes twice the other number.What are the numbers

Nov 29, 2007 | Computers & Internet

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