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First translate the various statements of the problem into equations. then try to solve the equations. It won't do much good if I just gave you the answers.

Sep 27, 2014 | Mathsoft StudyWorks! Middle School Deluxe...

That isn't an equation since there's no equal sign ("="). A simpler form of the expression is 4fg + 17g.

Sep 17, 2013 | Mathsoft StudyWorks! Middle School Deluxe...

Start by combining like terms on each side of the equation.

Remember, when working with variables the real numbers always come last in the equation(i.e. 5+x-7=x+5-7)

Once you have this completed move all variables to one side and all whole numbers to the other side. Solve from there.

Remember, when working with variables the real numbers always come last in the equation(i.e. 5+x-7=x+5-7)

Once you have this completed move all variables to one side and all whole numbers to the other side. Solve from there.

May 17, 2012 | MathRescue Word Problems Of Algebra Lite

I believe some minimal amount of knowledge of the concept will go a long way to teach you any subject.

When you say solve in Math, you mean solve an equation. An equation is a mathematical expression (with some unknown) that is equal to some other expression, usually a known value. That requires an = sign. However you do not have one.

All you can do is write the expression in as compact a form as possible. In this case, you combine the two like-terms that have the variable n to get 3n.

You expression is therefore 3n-3000. Period.

When you say solve in Math, you mean solve an equation. An equation is a mathematical expression (with some unknown) that is equal to some other expression, usually a known value. That requires an = sign. However you do not have one.

All you can do is write the expression in as compact a form as possible. In this case, you combine the two like-terms that have the variable n to get 3n.

You expression is therefore 3n-3000. Period.

Jan 12, 2012 | SoftMath Algebrator - Algebra Homework...

**Solve (***x*+ 2)(*x*+ 3) = 12.

- It is very common for students to see this type
of problem, and say:

solve to get x = 10 and x = 9. That was easy!"

So, tempting though it may be, I cannot set each of the factors above equal to the other side of the equation and "solve". Instead, I first have to multiply out and simplify the left-hand side, then subtract the 12 over to the left-hand side, and re-factor. Only then can I solve.

- (

(

Jul 17, 2011 | H. B. Enterprises Quadratic Solver

Hmmm ... 15/60

Since 60 can be divided evenly by 15, then let's start there:

15 divided by 15 is equal to 1. (correct?)

60 divided by 15 is equal to 4. (correct?)

Then:

15/60 =

(by the way, the common divisor is 15)

Aug 14, 2010 | Mathsoft Solving and Optimization...

Let A = number of adult tickets and S = number of senior tickets.

The total number of tickets is 444. This equals A + S.

444 = A + S

Total receipts were $7345. This can be represented as:

7345 = A*20 + S*15

Solve for A in first equation.

A = 444 - S

Substitute this into the 2nd equation for A

7345 = (444 - S)*20 + S*15

Solve for S

7345 = 8880 - 20*S + 15*S

7345 = 8880 - 5*S

-1535 = -5*S

307 = S

Therefore there were 307 senior tickets sold.

The number of adult tickets would be 444-307 = 137

The total number of tickets is 444. This equals A + S.

444 = A + S

Total receipts were $7345. This can be represented as:

7345 = A*20 + S*15

Solve for A in first equation.

A = 444 - S

Substitute this into the 2nd equation for A

7345 = (444 - S)*20 + S*15

Solve for S

7345 = 8880 - 20*S + 15*S

7345 = 8880 - 5*S

-1535 = -5*S

307 = S

Therefore there were 307 senior tickets sold.

The number of adult tickets would be 444-307 = 137

May 14, 2010 | SoftMath Algebrator - Algebra Homework...

Convert what you know into a couple of equations. You'll need two equations because there are two unknowns. Call them X = pounds of nuts that sell for .85/lb and Y = pounds of nuts selling for .55/lb.

Equation a): X+Y=60 (total weight sold is 60 lbs)

Equation b): .85X+.55Y=45.00 (because we want to sell 60 lbs at .75/lb)

Rearrange a) to X=60-Y (subtract Y from both sides)

Plug this into equation b) and solve it for Y:

.85X+.55Y=45.00

.85(60-Y)+.55Y=45.00

51.00 - .85Y + .55Y = 45.00

51.00 - .30Y = 45.00

6.00 = .30Y

Y = 6.00/.30 = 20 lbs

From equation a) then, X = 40 lbs. Check the results by solving equation b).

.85x40 + .55x20 = 34.00 + 11.00 = 45.00 (checks!)

(If either of those nuts is pistachios, where do I send my money? That's a good price and I want some!)

Equation a): X+Y=60 (total weight sold is 60 lbs)

Equation b): .85X+.55Y=45.00 (because we want to sell 60 lbs at .75/lb)

Rearrange a) to X=60-Y (subtract Y from both sides)

Plug this into equation b) and solve it for Y:

.85X+.55Y=45.00

.85(60-Y)+.55Y=45.00

51.00 - .85Y + .55Y = 45.00

51.00 - .30Y = 45.00

6.00 = .30Y

Y = 6.00/.30 = 20 lbs

From equation a) then, X = 40 lbs. Check the results by solving equation b).

.85x40 + .55x20 = 34.00 + 11.00 = 45.00 (checks!)

(If either of those nuts is pistachios, where do I send my money? That's a good price and I want some!)

Mar 19, 2010 | SoftMath Algebrator - Algebra Homework...

Assuming that band A charges a flat price, their price would simply be

A = 600

Band B's price would be

B = 350 + 1.25X

where X = number of tickets sold.

Set them equal and solve for X to figure the break-even point:

600 = 350 + 1.25X

250/1.25 = X

X = 200

If you have fewer than 200 people, Band B is the better deal; more than 200, you're better off with Band A.

A = 600

Band B's price would be

B = 350 + 1.25X

where X = number of tickets sold.

Set them equal and solve for X to figure the break-even point:

600 = 350 + 1.25X

250/1.25 = X

X = 200

If you have fewer than 200 people, Band B is the better deal; more than 200, you're better off with Band A.

Dec 18, 2009 | SoftMath Algebrator - Algebra Homework...

This is easy. First these brackets ( ) have a three numbers followed by an x y and z, the brackets mean we should multiply the like amounts: but first lets group like amounts by adding them up 3x+16x+6x= 25x then 8y+9y+11y=28y, now z...13z+14z=27z now the otherside of the equation which is always after the equal sign is 326+453=779, so now it is more simplified by combining like amounts:so now we have 25x+28y++27z=779 so now we must balance both sides of thr equation, what we do to the left side of the equal sign, we must also do to the right side of the = sign, so we need to get x by itself, so we minus 25 and are left with just an x, then if we take 25 off of the other side of the = sign, we must take 779-25 so now x is on the left side by itself then the the right side is 754, so now the x is solved X=754, then you do the same for y and z.

Sep 22, 2009 | The Learning Company Achieve! Math &...

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