Question about Bagatrix Algebra Solved! 2005 (105101) for PC

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Solving systems of equations by elimination

3x+2y= 7
5x-2y= 1 is my problem.


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  • Anonymous Apr 21, 2009

    6x-5y=47
    3y=-7-2x


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Hi joanmae jmeh;

You can add these equations just like you would numbers

3x + 2y = 7
5x - 2y = 1
-----------------------
8x =8
x=1
Now plug x = 1 back into either equation and you can solve for y
Y = 2

When you add the 2 equations together the +2y and the -2y cancel
out

Hope this helps Loringh Please leave a rating for me Thks

Posted on Dec 01, 2008

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Solve 4x-2y=8

Posted on Mar 02, 2009

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(0,2)

Posted on Dec 31, 2008

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How do I solve (3x-2y)2(3xy-3)


First, we will find y in terms of x. We will use the first equation to determine this.
4x+2y=2
We can subtract 4x from both sides:
2y=2-4x
And then divide both sides of the equation by two:
y=1-2x
Since we now have y in terms of x, we can substitute this into our second equation.
-3x-y=-3
-3x-(1-2x)=-3
Then, we can distribute the minus sign
-3x-1+2x=-3
-x-1=-3
Next, we can add 1 to both sides of the equation.


-x=-2
Finally, we divide both sides by negative one to isolate x.
x=2
Now that we have x's value, we can find y's value.
The first thing that we determined is:
y=1-2x
We can substitute in the value of x to this equation.
y=1-2x
plot-formula.mpl?expression=y=1-2%2a2&x=0003
y=1-4
y=-3
Therefore, we now have the values of both variables.
x=2
y=-3

Jan 13, 2015 | SoftMath Algebrator - Algebra Homework...

1 Answer

Chacha answers


It seems to me that you are trying to solve the quadratic equation
aX^2+bX+c=10 with a=-3, b=3, c=15 or -3X^2+3X+15=0.
Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation -3X^2+3X+15=0..
You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).
Discriminant is usually represented by the Greek letter DELTA (a triangle)
DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189
If the discriminant is positive (your case) the equation has two real solutions which are given by
Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2
Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2 or about -1.791287847
Here SQRT stands for square root.

Aug 17, 2014 | Computers & Internet

1 Answer

Chacha answers


It seems to me that you are trying to solve the quadratic equation
aX^2+bX+c=10 with a=-3, b=3, c=15 or -3X^2+3X+15=0.
Since the all the coefficients are multiples of 3, one can simplify the equation by dividing every thing by 3, leaving -X^2+X+5=0. But to avoid confusing you I will consider the original equation -3X^2+3X+15=0..
You must first find out if the equation has any real solutions. To do that you calculate the discriminant (you do not have to remember the name if you choose to).
Discriminant is usually represented by the Greek letter DELTA (a triangle)
DELTA =b^2-4*a*c =(3)^2-4*(-3)*(15)=189
If the discriminant is positive (your case) the equation has two real solutions which are given by
Solution1 =X_1=(-3-SQRT(189))/(-2*3)=(1+SQRT(21))/2
Solution2 =X_2=(-3+SQRT(189))/(-2*3)=(1-SQRT(21))/2 or about -1.791287847
Here SQRT stands for square root.

Aug 17, 2014 | SoftMath Algebrator - Algebra Homework...

1 Answer

Find the radius of the equation x^2+y^2-2x-2y=14


Try casting the equation of the circle into the form (x-h)^2+(y-k)^2=R^2. Here (h,k) would be the center and R the radius.
To do that complete the two squares.
x^2-2x=x^2-2x+1-1=(x^2-2x+1)-1=(x-1)^2 -1.
Do the same for the y terms.
y^2-2y=(y-1)^2 -1.
Substitute these two expressions in your original equation.
(x-1)^2+(y-1)^2 -1-1=14 or (x-1)^2+(y-1)^2=14+2=16
The radius is square root of 16 or 4, and the center is C(1,1).

Sep 20, 2011 | SoftMath Algebrator - Algebra Homework...

1 Answer

Four years ago allan was three less than twice roys age in 5years allan will be 6yeras older than roy how old are they?


Allan is 19 and Roy is 13.

Solution:

First we have 2 variables, their ages: I used Allan = x & Roy = y
Equation 1: X - 4 = 2*(Y-4) - 3
We can ignore the 5 years in the second part of the statement. Allan will always be 6 years older than Roy whether it be 5 years from now or ten years form now.
Equation 2: X = Y + 6

Substitute Y + 6 for X in equation 1:
X - 4 = 2*(Y-4) - 3 becomes Y + 6 - 4 = 2*(Y-4) - 3
That simplifies to Y + 2 = 2Y - 8 - 3
Rewrite it again: Y + 2 = 2Y - 11
Add 11 to both sides: Y + 13 = 2Y
Subtract Y from both sides: 13 = Y

Now plug 13 in for y in Equation 2
X = Y + 6
X = 13 + 6
X = 19

Oct 08, 2009 | Vivendi Math Blaster Algebra (03763) for...

2 Answers

X-3y=5 3x-2y=1


2y - x = 3
x = 3y - 5

Add the two equations side by side,

2y - x + x = 3 + 3y - 5

2y = 3y - 2

y = 2

Plug this in the second equation to get x,

x = 3(2) - 5

x = 1

So the solution is x = 1, y = 2

or in ordered pair notation (1, 2)

Jun 29, 2009 | Computers & Internet

2 Answers

Find the y coordinate in the solution of -3x+y=5 if x=1


This is the process of how you would solve this.

-move the -3x over to the right hand side, so you have:
y = 5 + 3x

- since you know what x is, plug in the x which is 1:
y = 5 + 3(1)

- solve the equation
y = 5+3

y = 8, so the solution is 8.

Dec 16, 2008 | SoftMath Algebrator - Algebra Homework...

5 Answers

Algebra 1


B. 2((2-Y)/3)-Y=3
2(2-Y)-Y=9
4-2Y-Y=9
-3Y=9-4
-3Y=5
-Y=5/3
Y=-1.67

A. 3X+(-1.67)=2
3X-1.67=2
3X=2+1.67
3X=3.67
X=3.67/3
X=1.22

Nov 05, 2007 | SoftMath Algebrator - Algebra Homework...

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Your friend John asks you for advice concerning life insurance. John is 32 years old and graduated from law school last year. he currently earns $48,000 per year as a first year attorney. John is married and has two children, Billy, age 10, and Sarah, age 4. John's wife, Mary, is a professor who currently earns $58,000 per year. Mary is 34 years old. John and Mary pay $1,700 per month for their home mortgage, which will be paid off in 20 years. The interest rate on their mortgage is 4.5%. (Their current equity in the home is $75,000.) The couple owns two cars, both 8 years old, and personal property (such as clothes, electronics, furniture, etc.) values at $45,000. Their investments have been used up paying for John's law school education, so they currently have only $1,000 in savings and checking accounts, and $2,000 in a mutual fund. John has no life insurance. Mary has $100,000 of life insurance provided by her employer. mary's pension plus social security are expected to total $45,000 per year, beginning when she is 67 years old. If John should die, Mary would receive approximately $10,000 per year from social security until Sarah reaches age 18. John and Mary spend most of their current income, although they do try to save about $50 per month. Their investments earn approximately 5% per year. In addition to their home mortgage, John has a student loan of $15,000 that he must start making payments on in 6 months. he plans to pau back the loan in 5 years and the loan's interst rate is 6% per year. Given that Mary enjoys a flexible work schedule, and because Mary's mother lives close by and watches the kids two days per week, the currently are not paying any child care expenses.

Nov 22, 2013 | Bagatrix Algebra Solved! 2005 (105101) for...

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Your friend John asks you for advice concerning life insurance. John is 32 years old and graduated from law school last year. he currently earns $48,000 per year as a first year attorney. John is married and has two children, Billy, age 10, and Sarah, age 4. John's wife, Mary, is a professor who currently earns $58,000 per year. Mary is 34 years old. John and Mary pay $1,700 per month for their home mortgage, which will be paid off in 20 years. The interest rate on their mortgage is 4.5%. (Their current equity in the home is $75,000.) The couple owns two cars, both 8 years old, and personal property (such as clothes, electronics, furniture, etc.) values at $45,000. Their investments have been used up paying for John's law school education, so they currently have only $1,000 in savings and checking accounts, and $2,000 in a mutual fund. John has no life insurance. Mary has $100,000 of life insurance provided by her employer. mary's pension plus social security are expected to total $45,000 per year, beginning when she is 67 years old. If John should die, Mary would receive approximately $10,000 per year from social security until Sarah reaches age 18. John and Mary spend most of their current income, although they do try to save about $50 per month. Their investments earn approximately 5% per year. In addition to their home mortgage, John has a student loan of $15,000 that he must start making payments on in 6 months. he plans to pau back the loan in 5 years and the loan's interst rate is 6% per year. Given that Mary enjoys a flexible work schedule, and because Mary's mother lives close by and watches the kids two days per week, the currently are not paying any child care expenses.

Nov 22, 2013 | Bagatrix Algebra Solved! 2005 (105101) for...

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