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It would be easier to add the first and last number, divide by two (you are finding the average), and multiply by the amount of numbers in the sequence (100). It is a formula, but it is an easier way to remember it.

Posted on May 13, 2009

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Posted on Jan 02, 2017

A long, fairly thorough way that shows the thinking behind it (usually considerably shorthanded in practice):

1) Rewrite the (negative-signed) elements of the equation so that their signs are clearly attached to them and cannot be confused with operations [you could also add the + in front of the positive-signed elements as well] -->

2.93 + 19j = -j + -5.82 + -11.25

2) Add j to both sides to consolidate all the j's on the same side of the equation [adding the same thing to both sides doesn't change the balance/value of the equation] --> 2.93 + 19j +j = +j +-j + -5.82 + -11.25 --> 2.93 + 20j = -5.82 + -11.25

3) Subtract 2.93 from both sides so that the j's are all by themselves on one side of the equation --> 2.93 + -2.93 + 20j = -5.82 + -11.25 + -2.93 --> 20j = -5.82 + -11.25 + -2.93

4) Add up the numbers on the right and rewrite the equation --> 20j = -20

5) Solve for j by dividing both sides by 20 [j's coefficient] --> j = -1

6) Test the answer in the left side of the equation --> 2.93 + 19(-1) --> 2.93 + -19 --> -16.07

7) Test the answer in the right side of the equation --> -(-1) + -5.82 + -11.25 --> 1 + -5.82 + -11.25 --> -16.07

8) Compare and validate: -16.07 = -16.07

1) Rewrite the (negative-signed) elements of the equation so that their signs are clearly attached to them and cannot be confused with operations [you could also add the + in front of the positive-signed elements as well] -->

2.93 + 19j = -j + -5.82 + -11.25

2) Add j to both sides to consolidate all the j's on the same side of the equation [adding the same thing to both sides doesn't change the balance/value of the equation] --> 2.93 + 19j +j = +j +-j + -5.82 + -11.25 --> 2.93 + 20j = -5.82 + -11.25

3) Subtract 2.93 from both sides so that the j's are all by themselves on one side of the equation --> 2.93 + -2.93 + 20j = -5.82 + -11.25 + -2.93 --> 20j = -5.82 + -11.25 + -2.93

4) Add up the numbers on the right and rewrite the equation --> 20j = -20

5) Solve for j by dividing both sides by 20 [j's coefficient] --> j = -1

6) Test the answer in the left side of the equation --> 2.93 + 19(-1) --> 2.93 + -19 --> -16.07

7) Test the answer in the right side of the equation --> -(-1) + -5.82 + -11.25 --> 1 + -5.82 + -11.25 --> -16.07

8) Compare and validate: -16.07 = -16.07

Nov 21, 2017 | Math

500 minutes.If this is homework, be sure to show your work.

Jan 04, 2017 | Homework

First, we will find y in terms of x. We will use the first equation to determine this.

4x+2y=2

We can subtract 4x from both sides:

2y=2-4x

And then divide both sides of the equation by two:

y=1-2x

Since we now have y in terms of x, we can substitute this into our second equation.

-3x-y=-3

-3x-(1-2x)=-3

Then, we can distribute the minus sign

-3x-1+2x=-3

-x-1=-3

Next, we can add 1 to both sides of the equation.

-x=-2

Finally, we divide both sides by negative one to isolate x.

x=2

Now that we have x's value, we can find y's value.

The first thing that we determined is:

y=1-2x

We can substitute in the value of x to this equation.

y=1-2x

y=1-4

y=-3

Therefore, we now have the values of both variables.

x=2

y=-3

4x+2y=2

We can subtract 4x from both sides:

2y=2-4x

And then divide both sides of the equation by two:

y=1-2x

Since we now have y in terms of x, we can substitute this into our second equation.

-3x-y=-3

-3x-(1-2x)=-3

Then, we can distribute the minus sign

-3x-1+2x=-3

-x-1=-3

Next, we can add 1 to both sides of the equation.

-x=-2

Finally, we divide both sides by negative one to isolate x.

x=2

Now that we have x's value, we can find y's value.

The first thing that we determined is:

y=1-2x

We can substitute in the value of x to this equation.

y=1-2x

y=1-4

y=-3

Therefore, we now have the values of both variables.

x=2

y=-3

Jan 13, 2015 | SoftMath Algebrator - Algebra Homework...

Suppose the length of time taken is T and the wind speed is W. Also we will assume that the ground speed of the plane is exactly its top speed plus or minus the wind speed, with no losses anywhere. So

(180 - W) * T = 100

(180 + W) * T = 135

180T - WT = 100

180T +WT = 135

Add these 2 equations together

360T = 235 so T = 0.653 hrs or 39.17 min

Now subtract equation 1 from equation 2

2WT = 35 This is the equation you ask for in your question

W = 35 / 2 / 0.653 or 26.8 mph

Check this

(180 - 26.8) * 0.653 = 100 OK

(180 - W) * T = 100

(180 + W) * T = 135

180T - WT = 100

180T +WT = 135

Add these 2 equations together

360T = 235 so T = 0.653 hrs or 39.17 min

Now subtract equation 1 from equation 2

2WT = 35 This is the equation you ask for in your question

W = 35 / 2 / 0.653 or 26.8 mph

Check this

(180 - 26.8) * 0.653 = 100 OK

Nov 12, 2014 | Office Equipment & Supplies

99.9999 repeating is technically equivalent to 100, depending on what level math you're in.

For example, 100 / 3 = 33.3333...

but clearly 33.333 * 3 = 99.9999...

So multiplying both sides of my first equation by 3, we get 100 = 99.9999

If you are not looking for "a number equivalent to 100" but "an equation or set of numbers equivalent to 100", then there are many ways. For example:

99 + 9/9 = 99 + 1

And 99 + 1 = 100

For example, 100 / 3 = 33.3333...

but clearly 33.333 * 3 = 99.9999...

So multiplying both sides of my first equation by 3, we get 100 = 99.9999

If you are not looking for "a number equivalent to 100" but "an equation or set of numbers equivalent to 100", then there are many ways. For example:

99 + 9/9 = 99 + 1

And 99 + 1 = 100

Jan 16, 2014 | RXE160 Equivalent NTE16013-ECG POLYMERIC...

Apply what you learned, especially that this system is quite simple.

Elimination

1. entails eliminating one variable to find (in this case) a single equation involving the other variable.

2. Solve that new equation, meaning isolate the variable that was not eliminated.

3. Substitute the value found in the last step and replace it in one of the original equation to obtain the other variable.

x+y=10

x-y=-6

Add the left sides to get x+y+x-y=2x

Add the right sides of the system to obtain 10+(-6)=4

Write Sum of left sides =Sum of right sides or 2x=4.

Since this new equation involves only x, you can solve it for x, getting x=4/2=2

Now you know the value of x (=2)

Take one of the original equations (for example x+y=10) and put 2 in place of x.

The equation becomes 2+y=10

Solve it to obtain y=10-2=8

Thus your solution is x=2, y=8

Check: use one equation in which you substitute 2 for x and 8 for y: x-y=-6 becomes 2-8=-6

Verified.

In the general case you will have to multiply by certain values to obtain opposite coefficients for the same variable. Here that was not necessary because the coefficient of y is 1 in the first equation and -1 in the second.

Elimination

1. entails eliminating one variable to find (in this case) a single equation involving the other variable.

2. Solve that new equation, meaning isolate the variable that was not eliminated.

3. Substitute the value found in the last step and replace it in one of the original equation to obtain the other variable.

x+y=10

x-y=-6

Add the left sides to get x+y+x-y=2x

Add the right sides of the system to obtain 10+(-6)=4

Write Sum of left sides =Sum of right sides or 2x=4.

Since this new equation involves only x, you can solve it for x, getting x=4/2=2

Now you know the value of x (=2)

Take one of the original equations (for example x+y=10) and put 2 in place of x.

The equation becomes 2+y=10

Solve it to obtain y=10-2=8

Thus your solution is x=2, y=8

Check: use one equation in which you substitute 2 for x and 8 for y: x-y=-6 becomes 2-8=-6

Verified.

In the general case you will have to multiply by certain values to obtain opposite coefficients for the same variable. Here that was not necessary because the coefficient of y is 1 in the first equation and -1 in the second.

Aug 16, 2011 | Casio Office Equipment & Supplies

You have two variables on the question. That is the Speed of the Train and the actual Time taken.

So you shouold be have two equations to resolve the two variables.

Lets assume the speed to be x and the actual time in minutes to be y.

So the 1st equation,

If the train goes with the actual or the normal speed x the train reaches within the time y.

we know that speed = distance X Time

so X = Distance x Y or

Distance = X/Y ------- 1

Next the 2nd equation.

[{(12.5/100) x X} + X] = Distance x (y-20) or

Distnace = [{(12.5/100) x X} + X] / (y-20) ------ 2

Now you can equate 1 and 2 to get the results.

So you shouold be have two equations to resolve the two variables.

Lets assume the speed to be x and the actual time in minutes to be y.

So the 1st equation,

If the train goes with the actual or the normal speed x the train reaches within the time y.

we know that speed = distance X Time

so X = Distance x Y or

Distance = X/Y ------- 1

Next the 2nd equation.

[{(12.5/100) x X} + X] = Distance x (y-20) or

Distnace = [{(12.5/100) x X} + X] / (y-20) ------ 2

Now you can equate 1 and 2 to get the results.

Nov 22, 2010 | Office Equipment & Supplies

Hi joanmae jmeh;

You can add these equations just like you would numbers

3x + 2y = 7

5x - 2y = 1

-----------------------

8x =8

x=1

Now plug x = 1 back into either equation and you can solve for y

Y = 2

When you add the 2 equations together the +2y and the -2y cancel

out

Hope this helps Loringh Please leave a rating for me Thks

You can add these equations just like you would numbers

3x + 2y = 7

5x - 2y = 1

-----------------------

8x =8

x=1

Now plug x = 1 back into either equation and you can solve for y

Y = 2

When you add the 2 equations together the +2y and the -2y cancel

out

Hope this helps Loringh Please leave a rating for me Thks

Dec 01, 2008 | Bagatrix Algebra Solved! 2005 (105101) for...

Lets say Your

MRP = 199

BESTSALE = 130

Now you want to calculate that howmuch percentage of BESTSALE i.e 130, will be added to get MRP i.e. 199.

If m right what do you want, then use the following formula:

Percentage = ((MRP/BESTSALE) - 1) x 100

In your case 199/130 = 1.5307....

So 1.5307 - 1 = 0.5307

Then 0.5307 x 100 = 53.07 %

Thanks

Iqbal

MRP = 199

BESTSALE = 130

Now you want to calculate that howmuch percentage of BESTSALE i.e 130, will be added to get MRP i.e. 199.

If m right what do you want, then use the following formula:

Percentage = ((MRP/BESTSALE) - 1) x 100

In your case 199/130 = 1.5307....

So 1.5307 - 1 = 0.5307

Then 0.5307 x 100 = 53.07 %

Thanks

Iqbal

Mar 10, 2008 | Office Equipment & Supplies

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