Question about Computers & Internet

Ad

I also got 422.5km/h..

how i got it...formula is

AVE SPEED = TOTAL DISTANCE / TOTAL TIME

Posted on Sep 10, 2009

Ad

422.5 Km./Hr.

Posted on Nov 27, 2008

Ad

Hi,

a 6ya Technician can help you resolve that issue over the phone in a minute or two.

Best thing about this new service is that you are never placed on hold and get to talk to real repair professionals here in the US.

click here to Talk to a Technician (only for users in the US for now) and get all the help you need.

Goodluck!

Posted on Jan 02, 2017

To travel 6km in half an hour, you need to travel 12kph.

Sep 10, 2014 | Cars & Trucks

278 - 128 = 150 traveled in 2 hours...

150/2 = 75km/hr

heatman101

150/2 = 75km/hr

heatman101

Jul 12, 2011 | Sport & Outdoor - Others

The following are examples of expressions:

2

*x*

3 + 7

2 ×*y* + 5

2 + 6 × (4 - 2)

*z* + 3 × (8 - *z*)

Example:

Roland weighs 70 kilograms, and Mark weighs*k* kilograms. Write an expression
for their combined weight. The combined weight in kilograms of these two people
is the sum of their weights, which is 70 + *k*.

Example:

A car travels down the freeway at 55 kilometers per hour. Write an expression for the distance the car will have traveled after*h* hours. Distance equals rate
times time, so the distance traveled is equal to 55 × *h*..

Example:

There are 2000 liters of water in a swimming pool. Water is filling the pool at the rate of 100 liters per minute. Write an expression for the amount of water, in liters, in the swimming pool after*m* minutes. The amount of water added
to the pool after *m* minutes will be 100 liters per minute times *m*,
or 100 × *m*. Since we started with 2000 liters of water in the pool,
we add this to the amount of water added to the pool to get the expression 100 ×
*m *+ 2000.

To evaluate an expression at some number means we replace a variable in an expression with the number, and simplify the expression.

Example:

Evaluate the expression 4 ×*z* + 12 when *z* = 15.

We replace each occurrence of*z* with the number 15, and simplify using the
usual rules: parentheses first, then exponents, multiplication and division, then
addition and subtraction.

4 ×*z* + 12 becomes

4 × 15 + 12 =

60 + 12 =

72

Example:

Evaluate the expression (1 +*z*) × 2 + 12 ÷ 3 - *z* when
*z* = 4.

We replace each occurrence of z with the number 4, and simplify using the usual rules: parentheses first, then exponents, multiplication and division, then addition and subtraction.

(1 +*z*) × 2 + 12 ÷ 3 - *z* becomes

(1 + 4) × 2 + 12 ÷ 3 - 4 =

5 × 2 + 12 ÷ 3 - 4 =

10 + 4 - 4 =

10.

**hope that help you**

2

3 + 7

2 ×

2 + 6 × (4 - 2)

Example:

Roland weighs 70 kilograms, and Mark weighs

Example:

A car travels down the freeway at 55 kilometers per hour. Write an expression for the distance the car will have traveled after

Example:

There are 2000 liters of water in a swimming pool. Water is filling the pool at the rate of 100 liters per minute. Write an expression for the amount of water, in liters, in the swimming pool after

To evaluate an expression at some number means we replace a variable in an expression with the number, and simplify the expression.

Example:

Evaluate the expression 4 ×

We replace each occurrence of

4 ×

4 × 15 + 12 =

60 + 12 =

72

Example:

Evaluate the expression (1 +

We replace each occurrence of z with the number 4, and simplify using the usual rules: parentheses first, then exponents, multiplication and division, then addition and subtraction.

(1 +

(1 + 4) × 2 + 12 ÷ 3 - 4 =

5 × 2 + 12 ÷ 3 - 4 =

10 + 4 - 4 =

10.

Jun 22, 2011 | LeapFrog Turbo Twist Math Cartridge 5th...

126km/21.5hr = 5.86km/hr This is how far he travels each hour.

Once you find this out you multiply by 3 hours because you want to know how many kilometers he traveled in 3 hours not each hour. 3 * 5.86= 35.16 km.

Ben traveled 35.16 Kilometers after 3 hours.

Once you find this out you multiply by 3 hours because you want to know how many kilometers he traveled in 3 hours not each hour. 3 * 5.86= 35.16 km.

Ben traveled 35.16 Kilometers after 3 hours.

Jun 09, 2011 | Sharp EL-2630P Calculator

To start out, you need to figure out what the equation for the problem is. You know a few things that should help you along the way:

The 6 at the front is how many hours the first train traveled. the 4 is the hours the second train traveled. the 60 is (4*15) which is how much faster the second train was going. the 580 is the total distance between them.

Solve for x

10x=520

x=52

So the westbound train was going 52 km/h and the east bound train was going 67km/h.

- The trains are 580 km apart
- one train traveled for 6 hours
- the other train traveled for 4 hours
- one train is going 15km/h faster than the other.

The 6 at the front is how many hours the first train traveled. the 4 is the hours the second train traveled. the 60 is (4*15) which is how much faster the second train was going. the 580 is the total distance between them.

Solve for x

10x=520

x=52

So the westbound train was going 52 km/h and the east bound train was going 67km/h.

May 03, 2011 | Texas Instruments TI-30 XIIS Calculator

Time taken = 2 x 450 / 200

= 4.5 hours

= 4.5 hours

Sep 22, 2010 | Acer Computers & Internet

Ms. Reck's trip on her bike took 3 times longer (48/16ths) so the service station was 48 km from her home. It took her one hour (1x48km)= 48km) to get there and 3 hours to get home (3x16=48km) for a total of 4 hours...

Nov 22, 2009 | The Learning Company Achieve! Math &...

The ones associated with the little circles? One dial is for seconds, one for minutes, and one for hours. The seconds one should be applicable for time. The minute and hour, along with the big seconds hand that is centre mounted are for the chronograph function.

Jan 23, 2009 | Tissot PRS 200 Wrist Watch

Jan 22, 2018 | Computers & Internet

Jan 22, 2018 | Computers & Internet

186 people viewed this question

Usually answered in minutes!

×