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Find largest number given three numbers in visual basic

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Enter a;
enter b;
enter c;
if a>=b and a>c
print "a is the greatest number"
then if b>=a and b>c
print "b is the greatest number"
then if a=b and a=c
print "a, b, c are equal"
if not print "c is the greatest number"

this is pseudocode.. or my drunken attempt to remember pseudocode... but I think the logic could work.

Posted on Nov 27, 2008

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Program of c to find largest and second larhest number of given 50 numbers using array


This code generates some random number to test.


#include <limits.h>
#include <stdio.h>
#include <stdlib.h>

int main()
{ findLargest();
return 0;
}

int findLargest()
{ int someNumbers[50];
int i;

// to generate some numbers for us to test
for(i=0; i<50; i++)
// generate a random number between 0-100
someNumbers[i] = rand() % 100;

// for keeping track of numbers, set as smallest possible
int largest = INT_MIN;
int largest2 = INT_MIN;

// go through each item in the array
for(i=0; i<50; i++)
{ // if bigger than our previous max, set as new max
if (someNumbers[i] > someNumbers[largest])
largest = i;
// if it's not been set as new max, and is bigger than current 2nd largest
else if(someNumbers[i] > someNumbers[largest2])
largest2 = i;

// for printing all numbers in the array
printf("%d | %d\n",i, someNumbers[i]);
}

// print largest numbers and their position in the array
printf("largest %d (pos %d).\n2nd largest %d (pos %d)",
someNumbers[largest],
largest,
someNumbers[largest2],
largest2
);

return 0;

}

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1 Answer

I have a problem


This is a common starter challenge in college and high school programming classes. While i'm not willing to code it for you, I can show you the methods you'll need to understand in order to approach the problem. The easiest way of doing this is by using a brute force method. Just keep testing the number to see if the remainder after dividing it with a number lower than it is zero. If so, it's a factor.
For example, If the number is 35 then pick a number just one lower than it that's not the number 1. Now divide the two numbers. 35/34 = a number with many decimal places after it, which means its not one of the factors of the number. However, eventually, you'll approach the number 7, and 35/7 = 5. This number has no decimal, meaning it IS a factor of 35, and also the largest non-zero factor of 35. Your algorithm can now stop, since it found the largest non-zero number.
Here's some pseudo-code:
int largestfactor(int number) {
int temp = number;
for(temp - 1; temp>=1; temp--) {
if (number % temp == 0) return temp
}
return temp
}
Something like that, with some bug tweaks will do it. The "%" sign is called a modulus. It's a standard c++ operator. Good luck, and remember to vote Fixya if you liked it.
The wikipedia article that helps you with better and more effecient algorithms can be found here.
Steven

Sep 15, 2008 | Operating Systems

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