Question about Sony Ericsson P1i

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P1 backup issue

Have a p1 for a year now,works more or less fine, except for the back up process. when connected to the computer the first few back-ups worked ok, since a few months now the phone stops the process, leaving the thing uncompleted.
had the same issue with my m600i earlier, in fact that was the reason to get the p1, seems time to get rid of it, or any solution?
thnx

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  • smiliemotor Nov 26, 2008

    :-( tried that, no help,- thnx.

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I had the same problem until I discovered that if I skiped the third party applications in my back up it went just fine.

Posted on Nov 26, 2008

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6ya6ya
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This can be due to drop damage causing an impact on the pallets, a failing head on the drive, a failed pre-amp on the arm or even a few circuits on the PCB board that are involved in the process.

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If the battery backup unit is over 2.5 years old then you will need to replace the battery. Go to your local electronics parts house or battery distributor. They will have the gel cell battery you need in stock. These units are just like small car batteries, after a few years of use they will break down and not hold a full charge. When this starts to happen the battery life is about to be over, it will hold less and less charge until one day no power at all and then the UPS will not power on. The UPS have a monitor circuit that will prevent them from powering up with a dead or missing battery. The replacement battery should run less than $20.

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Perform a hard reset of the BlackBerry smartphone.


1) Remove the battery cover from the back of the BlackBerry smartphone.
2) Remove the battery, and then reinsert it after a few seconds.
3) Replace the battery cover.

If the Problem continues

Perform these Steps:-

Use the following steps to back up a BlackBerry device:
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  2. Ensure that the BlackBerry device is connected correctly. The word Connected should be displayed at the bottom of the BlackBerry Desktop Manager screen.
  3. Double-click on the Backup and Restore icon.
  4. In the Backup and Restore screen, click Backup.
  5. Choose a location where you wish to save your backup file.
  6. Give the backup file a new name or leave the default name in the File Name field.
  7. Click Save.
  8. The BlackBerry device has now been fully backed up.
To delete all data from the BlackBerry smartphone
  1. On the Home screen of the BlackBerry smartphone, click Options.
  2. click Security Options Then Select General Settings.
  3. Click Menu button then Select Wipe Handheld.
  4. you will get message click Continue.
  5. they Type Blackberry, Press Enter.

To Restore the Data to your Blackberry Handheld 1. Connect the BlackBerry device to the computer using a USB cable, and open the BlackBerry Desktop Manager. 2. Ensure that the BlackBerry device is connected correctly. The word Connected should be displayed at the bottom of the BlackBerry Desktop Manager screen. 3. Double-click on the Restore Tab. 4. Navigate to the backup file you want to restore to your BlackBerry smartphone. 5. Double-click the backup (.ipd) file. 6. Restore Process will start.

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Step#2
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Step#3

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How to be solve banker algorithm?example


I m providing you this from my college notes

Banker's Algorithm


* multiple instances of resource types IMPLIES cannot use resource-allocation graph

* banks do not allocate cash unless they can satisfy customer needs when a new process enters the system

* declare in advance maximum need for each resource type

* cannot exceed the total resources of that type

* later, processes make actual request for some resources

* if the the allocation leaves system in safe state grant the resources

* otherwise, suspend process until other processes release enough resources



Banker: Data Structures define MAXN 10 /* maximum number of processes */
#define MAXM 10 /* maximum number of resource types */
int Available[MAXM]; /* Available[j] = current # of unused resource j */
int Max[MAXN][MAXM]; /* Max[i][j] = max demand of i for resource j */
int Allocation[MAXN][MAXM]; /* Allocation[i][j] = i's current allocation of j*/
int Need[MAXN][MAXM]; /* Need[i][j] = i's potential for more j */
/* Need[i][j] = Max[i][j] - Allocation[i][j] */

Notation:

X <= Y iff X[i] <= Y[i] for all i

(0,3,2,1) is less than (1,7,3,2)

(1,7,3,2) is NOT less than (0,8,2,1)

Each row of Allocation and Need are vectors: Allocation_i and Need_i



Banker: Example

Initially:

Available
A B C
10 5 7

Later Snapshot:

Max - Allocation = Need Available
A B C A B C A B C A B C
P0 7 5 3 0 1 0 7 4 3 3 3 2
P1 3 2 2 2 0 0 1 2 2
P2 9 0 2 3 0 2 6 0 0
P3 2 2 2 2 1 1 0 1 1
P4 4 3 3 0 0 2 4 3 1



Banker: Safety Algorithm

* consider some sequence of processes

* if the first process has Need less than Available

* it can run until done

* then release all of its allocated resources

* allocation is increased for next process

* if the second process has Need less than Available

* ...

* then all of the processes will be able to run eventually

* IMPLIES system is in a safe state



Banker: Safety Algorithm

STEP 1: initialize
Work := Available;
for i = 1,2,...,n
Finish[i] = false
STEP 2: find i such that both
a. Finish[i] is false
b. Need_i <= Work
if no such i, goto STEP 4
STEP 3:
Work := Work + Allocation_i
Finish[i] = true
goto STEP 2
STEP 4:
if Finish[i] = true for all i, system is in safe state



Banker: Safety Example

Using the previous example, P1,P3,P4,P2,P0 satisfies criteria.

Max - Allocation = Need <= Work Available
A B C A B C A B C A B C
P1 3 2 2 2 0 0 1 2 2 3 3 2 3 3 2
P3 2 2 2 2 1 1 0 1 1 5 3 2
P4 4 3 3 0 0 2 4 3 1 7 4 3
P2 9 0 2 3 0 2 6 0 0 7 4 5
P0 7 5 3 0 1 0 7 4 3 10 4 7
10 5 7<<< initial system



Banker: Resource-Request Algorithm

STEP 0: P_i makes Request_i for resources, say (1,0,2)
STEP 1: if Request_i <= Need_i
goto STEP 2
else ERROR
STEP 2: if Request_i <= Available
goto STEP 3
else suspend P_i
STEP 3: pretend to allocate requested resources
Available := Available - Request_i
Allocation_i := Allocation_i + Request_i;
Need_i := Need_i - Request_i
STEP 4: if pretend state is SAFE
then do a real allocation and P_i proceeds
else
restore the original state and suspend P_i



Banker: Resource-Request Algorithm [129]

Say P1 requests (1,0,2)

Compare to Need_1: (1,0,2) <= (1,2,2)

Compare to Available: (1,0,2) <= (3 3 2)

Pretend to allocate resources:

Max - Allocation = Need Available
A B C A B C A B C A B C
P0 7 5 3 0 1 0 7 4 3 2 3 0<<<
P1 3 2 2 3 0 2<<< 0 2 0<<<
P2 9 0 2 3 0 2 6 0 0
P3 2 2 2 2 1 1 0 1 1
P4 4 3 3 0 0 2 4 3 1

Is this safe? Yes: P1, P3, P4, P0, P2

Can P4 get (3,3,0)? No, (3,3,0) > (2,3,0) Available

Can P0 get (0,2,0)? (0,2,0) < (2,3,0) Available

Pretend: Available goes to (2,1,0)

Thanks And Regards

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