Question about Texas Instruments TI-86 Calculator

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I need help with square root functions

The problem is ^4 square root of 21.2846

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Hello,
The square root has a dedicated key sequence [2nd][V square root symbol]
Square root of 21.2846 is entered [2nd][V square root] 21.2846 [ENTER] .
The result is`4.614.
I suspect you want to calculate the 4th root of 21.2846. If it is the case you enter that as
21.2846 [^](1/4) =2.148
Square root can be also entered as [^](1/2)
Cube root is entered as [^] (1/3)

..
nth root is entered as [^](1/n)
Hope it helps.

Posted on Sep 23, 2009

Testimonial: "thanks sorry for the REALLY late reply!"

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SOURCE: Need Help Solving Exponential Functions ASAP!!!!

You can calculate =4^1.2 in Excel and get 5.278031643
And also in Excel you can determine what the square root of 2 is (2.506628274631) and then in Excel = 5 ^ 2.506628274631 = 56.5012395907155.

I know this is late but maybe it will help later. Assuming I am doing it right. Thanks!

Posted on Apr 15, 2009

  • 13 Answers

SOURCE: I need to use the square root sign but I need to

If you would like to a root other than a square root, first enter the root value (3, 4, 5, etc.) then press MATH. Then Press 5 and enter the value you want to take that root of. Press ENTER.

Posted on Jun 16, 2009

SOURCE: Square root on FX-83ES

make sure you havnt droppend your calculator as this can damage the chip, if so , re solder broken parts and it sshould work, this happened on mine and after i soldered it it is fixed.
online companies can fix it if you send it away

Posted on Sep 10, 2008

  • 7993 Answers

SOURCE: TI-15 square root Function

Hello,
You should enter it as follows [SQRT]36 ) [ENTER/=].
If you define some function f of a variable x you write that f(x), where the parentheses enclose the so-called argument (objet on wich the function acts). It seems that on this calculator the opening parenthesis is implicit: the calculator supplies it when you press [SQRT] but does not display it (a design flaw?). However the closing parenthesis must be entered by you to signifie to the function [SQRT] that you have finished entering the argument. Weird but one can live with it.
Hope it helps.

Posted on Sep 07, 2009

ur fortune
  • 85 Answers

SOURCE: I want to find the square root of a number and the

if it is a perfct square root then u will get a integer part.....if its not a perfect square root than obviously u will get decimal part........ u just check ur calculater in which mode it is......exit the radian and do it

Posted on Oct 15, 2009

6ya6ya
  • 2 Answers

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Posted on Jan 02, 2017

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