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(-4,6), m = 8

Y-y1 = m (x-x1)

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The equation of a straight line is given by y=mx + b where y if the y intercept on a graph and x is the x intercept on a graph and m is the slope of the line

Using the given information of ( -4, 6), m=8

-4 is the x intercept, 6 is the y intercept and the slope is 8.

Plugging these values into the y = mx + b gives 6 = (8) (-4) + b solving for b gives b = 32

Going back to the original equation of a straight line gives the equation of y = 8x + 32

Hope this helps Loringh PS Please leave a rating for me Thank you

Posted on Nov 19, 2008

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Probably something like p1 = (3,4); p2 = (5,8); the general form of this is p1=(x1,y1); p2=(x2,y2). The slope in this case is rise over run, in other words, the change in y divided by the change in x. This can be calculate between these two points as (y2-y1)/(x2-x1). In my sample above, this would be (8-4)/(5-3) = 4/2 = 2 giving the value of m.

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It's easier than it looks. It can help you to understand if you get some old fashioned graph paper and plot it so you can see what is happening.

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