Y-y1 = m (x-x1)

The equation of a straight line is given by y=mx + b where y if the y intercept on a graph and x is the x intercept on a graph and m is the slope of the line

Using the given information of ( -4, 6), m=8

-4 is the x intercept, 6 is the y intercept and the slope is 8.

Plugging these values into the y = mx + b gives 6 = (8) (-4) + b solving for b gives b = 32

Going back to the original equation of a straight line gives the equation of y = 8x + 32

Hope this helps Loringh PS Please leave a rating for me Thank you

Posted on Nov 19, 2008

It can often be done by inspection. Could you post the sequence of numbers? Make sure x1 is included.

Jan 13, 2015 | SoftMath Algebrator - Algebra Homework...

Assuming the 'standard form' is "slope-intercept", calculate the slope from the equation m = __y2-y1__ =__ 5 - 1__ = __ 4__ = -2

x2-x1 4 - 6 -2

The intercept can be found by substituting either of the two points into the equation y = mx + b

5 = (-2)4 + b

5 = (-8) + b

13 = b

(OR, using the other point, y = mx + b

1 = (-2)6 + b

1 = (-12) + b

13 = b )

Then expressing in general:

**y = (-2) x + 13**

x2-x1 4 - 6 -2

The intercept can be found by substituting either of the two points into the equation y = mx + b

5 = (-2)4 + b

5 = (-8) + b

13 = b

(OR, using the other point, y = mx + b

1 = (-2)6 + b

1 = (-12) + b

13 = b )

Then expressing in general:

Oct 10, 2014 | Educational & Reference Software

The rate of change for the function y=5x+4 is the coefficient 5 that multiplies the independent variable x. For a unit variation of x (x varies by 1) y varies by 5 units.

Between x1=2 to x2=3, y varies from y1=5*2+4=14 to y2=5*3+4=19.

The rate of change is defined as

**(variation in y)/(variation in x)=(19-14)/(3-2)=5**

Between x1=2 to x2=3, y varies from y1=5*2+4=14 to y2=5*3+4=19.

The rate of change is defined as

Sep 28, 2014 | SoftMath Algebrator - Algebra Homework...

Well (3+5)x(13-9)x1

Is that allowable?

Is that allowable?

Jul 26, 2014 | The Learning Company Achieve! Math &...

No, 1 is not a prime number. The decomposition of a number into prime factors must be unique so 2=1x2 is prime but since 1 can be written as 1=1x1x1x1....x1 with an arbitrary number of factors this opens up a can of worms as far as unicity of the decomposition is concerned. Conclusion: 1 has been ruled out as a prime number.

I hope that this gives you an idea why 1 is no longer considered prime.

I hope that this gives you an idea why 1 is no longer considered prime.

Jul 10, 2012 | Mathsoft StudyWorks! Middle School Deluxe...

Solve for Y first.

y= (1-3x)/-5

Then plug in a number for x and you'll get a Y value.

x= 0 y =-1/5

x1=1 y1= 2/5

(y-y1)/(x-x1) = m

m= your slope.

On that calculator you would do it the same way but graph it 1st and then pick to values that are easier to work with.

y= (1-3x)/-5

Then plug in a number for x and you'll get a Y value.

x= 0 y =-1/5

x1=1 y1= 2/5

(y-y1)/(x-x1) = m

m= your slope.

On that calculator you would do it the same way but graph it 1st and then pick to values that are easier to work with.

Nov 04, 2010 | MathAid Algebra II

x^2=-3x+28
x^2+3x - 28 = 0
D=9+112=121>0
x1=(-3+11)/2 = 4
x2=(-3-11)/2 = -7

Jun 03, 2010 | Bagatrix Precalculus Solved Full Version...

let sqrt of y =x

y to the power negative 1/2 = 1/ sqrt y

so our equation becomes

( 6x + 1 / 6x ) = 37

36x^2 -222 x + 1 =0

the roots of above quadratic equation are

x1=6.1621

and x2 =.0045

therefore y = x^2

y = 6.1621^2 = 37.971

and y=.0045^2 = .00002025

pls rate the solution if it was helpful.post your doubts i f u have any

y to the power negative 1/2 = 1/ sqrt y

so our equation becomes

( 6x + 1 / 6x ) = 37

36x^2 -222 x + 1 =0

the roots of above quadratic equation are

x1=6.1621

and x2 =.0045

therefore y = x^2

y = 6.1621^2 = 37.971

and y=.0045^2 = .00002025

pls rate the solution if it was helpful.post your doubts i f u have any

Apr 21, 2010 | SoftMath Algebrator - Algebra Homework...

slope of side lm by applying slope =(y2-y1)/(x2-x1)

slope of lm=0

slope of mn=5/-3 = -5/3

slope of ln= 5/3

so sum of slopes =0

slope of lm=0

slope of mn=5/-3 = -5/3

slope of ln= 5/3

so sum of slopes =0

Apr 06, 2010 | SoftMath Algebrator - Algebra Homework...

It depends on how complex the function is; there are different techniques. For a straight line of the standard form, usually shown as y=mx+b; this is a simple function of y in terms of x. So, determining the function in this case means finding values for m and b. --- m is the slope of the line, commonly called rise over run. Since your question asks in terms of coordinates, I would assume that you are looking at a problem giving you 2 points.

Probably something like p1 = (3,4); p2 = (5,8); the general form of this is p1=(x1,y1); p2=(x2,y2). The slope in this case is rise over run, in other words, the change in y divided by the change in x. This can be calculate between these two points as (y2-y1)/(x2-x1). In my sample above, this would be (8-4)/(5-3) = 4/2 = 2 giving the value of m.

To find the value of b (the y intercept) you need the value of y when x = 0. Since you already know that m, the slope is 2, consider a new point, call it p3 (x3,y3), pick either of the known points and solve the slope equation again, this time for y3. [m=(y3-y1)/(x3-x1)]. We know that x3 is 0, since we are trying to solve for y where that is true, so the equation becomes:

m=(y3-y1)/(-x1)

-x1*m=y3-y1

y3=y1-x1*m

y3 is really b in the standard form, since it is, by definition the intercept, or the value when x=0,

so

b=y1-x1*m -- this gives you the y intercept anytime you know the slope and one point on the line.

In the example, y1 = 4, x1=3 and we've already calculated m to be 2, so

b=4-3*2 = -2

So, the function would be

y = 2x -2

To check, plug in the values of the other point, p2, and see if they work

y2 = 2*x2 - 2

8=2*5-2

It's easier than it looks. It can help you to understand if you get some old fashioned graph paper and plot it so you can see what is happening.

Probably something like p1 = (3,4); p2 = (5,8); the general form of this is p1=(x1,y1); p2=(x2,y2). The slope in this case is rise over run, in other words, the change in y divided by the change in x. This can be calculate between these two points as (y2-y1)/(x2-x1). In my sample above, this would be (8-4)/(5-3) = 4/2 = 2 giving the value of m.

To find the value of b (the y intercept) you need the value of y when x = 0. Since you already know that m, the slope is 2, consider a new point, call it p3 (x3,y3), pick either of the known points and solve the slope equation again, this time for y3. [m=(y3-y1)/(x3-x1)]. We know that x3 is 0, since we are trying to solve for y where that is true, so the equation becomes:

m=(y3-y1)/(-x1)

-x1*m=y3-y1

y3=y1-x1*m

y3 is really b in the standard form, since it is, by definition the intercept, or the value when x=0,

so

b=y1-x1*m -- this gives you the y intercept anytime you know the slope and one point on the line.

In the example, y1 = 4, x1=3 and we've already calculated m to be 2, so

b=4-3*2 = -2

So, the function would be

y = 2x -2

To check, plug in the values of the other point, p2, and see if they work

y2 = 2*x2 - 2

8=2*5-2

It's easier than it looks. It can help you to understand if you get some old fashioned graph paper and plot it so you can see what is happening.

Jun 16, 2009 | Educational & Reference Software

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