Question about Super Tutor Trigonometry (ESDTRIG) for PC
Find the equation of the parabola with the vertex of (2,0) and focus of (2,2)
V (2,0) and Focus (2,2)
since the focus is 2 units above the vertex, the parabola opens upward
a is the focal length (distance between the vertex and the focus)
a = 2
(2 units above the vertex)
(x-h)^2 = 4a (y-k)
(x-2)^2 = 4(2) (y-0)
x^2 - 4x + 4 = 8 (y)
x^2 - 4x + 4 = 8y
x^2 - 4x - 8y + 4 = 0
**Answer: "(x-2)^2 = 8 (y)" or in expanded form "x^2 - 4x - 8y +4"
Posted on Jan 10, 2009
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Posted on Jan 02, 2017
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