Question about Super Tutor Trigonometry (ESDTRIG) for PC

Hi Jehho soria

Draw a right triangle with the vertical portion of the triangle representing the 37 meters of the light house The base of the triangle is the distance we are trying to find. If the angle of depression is 15 degrees, the other angle is 75 degrees. This is the angle from the boat to the top of the lighthouse.

so The Tangent of 75 degrees is equal to the side opposite the angle (the height of the lighthouse) divided by the side adjacent (the distance we are trying to find.

solving for the distance we get distance = 37 divided by the tangent of 37 degrees

Looking up the tangent of 15 degrees on google give .2679

dividing 137 by .2679=138,1 meters

Hope this helps Loringh PS Please leave a rating for me.

Posted on Nov 17, 2008

Given alpha is .623and side a is 12 find alpha and side b and c

Posted on Dec 13, 2008

SOURCE: trigonometry

what is the value of sin30.28?

how can it be found using log table?

ravi_kant66@hotmail.com

Posted on Sep 09, 2008

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Posted on Jan 02, 2017

Assuming the dam face is vertical, 3017 feet.

If this is homework, be sure to show your work.

If this is homework, be sure to show your work.

Jul 12, 2014 | Super Tutor Trigonometry (ESDTRIG) for PC

If I understand your terminology correctly, you have a triangle with a hypotenuse of 6' 3-13/16" and a side opposite the angle you wish to find with a length of 8" (and a side adjacent to the angle you wish to find with a length of 6' 3-3/8") Trigonometry says that the sine of an angle is the length of the opposite side divided by the hypotenuse. (all units must be the same, so convert everything to inches)

So sine (angle) = 8/(6 * 12 + 3 + 13/16)

sine (angle = 8/(75.8125)

sine(angle) = .105523

angle = arc-sine(.105523)

angle = 6.0573 degrees (from tables, calculator, computer etc)

So sine (angle) = 8/(6 * 12 + 3 + 13/16)

sine (angle = 8/(75.8125)

sine(angle) = .105523

angle = arc-sine(.105523)

angle = 6.0573 degrees (from tables, calculator, computer etc)

Jun 07, 2014 | CyberEd Trigonometry Problem Solver

About 61.665 meters.

Feb 12, 2014 | Educational & Reference Software

That would be 1199 / tan 72.2 or 385 ft

Sep 15, 2013 | Super Tutor Trigonometry (ESDTRIG) for PC

height =50

length = 60

angle=x

tangent(x)=50/60

tangent(x)=0.833

x=39.8 degree

length = 60

angle=x

tangent(x)=50/60

tangent(x)=0.833

x=39.8 degree

Mar 01, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

ð XAC = ð ACB (Angle of elevation= Angle of depression)

AB = 5 Yards

BC = ?

Now Tan C= AB/BC

BC = AB/ Tan C

BC = 5 / Tan 28 Yards

BC = 5/.531709 Yards

BC = 9.403632 Yards

AB = 5 Yards

BC = ?

Now Tan C= AB/BC

BC = AB/ Tan C

BC = 5 / Tan 28 Yards

BC = 5/.531709 Yards

BC = 9.403632 Yards

Jan 02, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

Given AC = 2675 feet

ð XAC= 14 degree

Therefore ð ACB = 14

Now Sin C= AB/AC

AB = AC . Sin C

AB = 2675 * Sin 14 feet

AB = 2675 * 0.241922 feet

AB = 647.1411 feet

ð XAC= 14 degree

Therefore ð ACB = 14

Now Sin C= AB/AC

AB = AC . Sin C

AB = 2675 * Sin 14 feet

AB = 2675 * 0.241922 feet

AB = 647.1411 feet

Jan 02, 2009 | Super Tutor Trigonometry (ESDTRIG) for PC

prove root 5 is irrational

Jul 11, 2008 | Parsons QuickVerse 7 Essentials (fe11044)...

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