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How to find perimeter of the triangle whose vertices are the ff.points A(6,2)B(4,3)C(0,1)

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I'm sure there are easier ways to do this but the "brute force" method is to label point A as x1, y1; point b as x2, y2 and point c as x3,y3. Then just do square root of the sum of: (x2-x1)squared+(y2-y1)squared. Save this into memory 'A'. Now do the same for x2,y2 to x3,y3 and add this to the number saved in 'A' and do it once more for x3, y3 to x1, y1 and add to the number in 'A' to get the result.

Posted on Dec 22, 2008

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Posted on Jan 02, 2017

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We can use BC or AB as the base.

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We can now put the length and height into the formula to calculate the area of the triangle.

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1 Answer

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We can now put the length and height into the formula to calculate the area of the triangle.

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