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Exponential growth an amount was invested 2 yrs. ago at a rate of 7% became much was the amount?

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Rounding off some numbers to keep it simple would give a starting amount of 4500


Posted on Nov 07, 2008

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How do I enter exponential growth or decay functions and their shifts?

The formula for exponential growth and exponential decay is

A =I (1 + r)^n, where A is the amount, I is the initial amount, r is the rate of exponential growth or decay and n is the number of periods.

For example, if we start with 100 units and the growth is 5% per period, we get the equation A = 100 (1+0.5) ^n. When n is 0, anything to the exponent 0 is 1, so we start with 100 units. When n is 1, we get 105 units.

Similarly, if a car costing $50,000 depreciates in value 30% per year, we have A= 50000 (1-0.3)^n, Again, when n = 0, anything to the power of 0 is 1, so we start at $50,000. When n=1, A = 35,000. When n = 2, A = $24,500.

Good luck,


Nov 05, 2015 | Texas Instruments Ti-30Xs Multiview...

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I have a starting amount of $2,125. I invest some of it in a bank that pays 4% a year and some in another back that pays 5% a year. After one year I have earned $100. How much money did I invest in ea

There are 2 values for interest, say R and r, and R = 0.05, r = 0.04

There are 2 values for the amount earned, from the 2 banks, say I and i, and we know I + i = 100

There are 2 values for principal invested, say P and p, and we know P + p = 2125

There is only one value for period, say t = 1

So then I = P * 0.05 * 1 and
i = p * 0.04 * 1 and
I + i = 100 and
P + p = 2125


0.05P + 0.04p = 100
P + p = 2125
P = 2125 - p
0.05 ( 2125 - p) +0.04p = 100
106.25 - 0.05p + 0.04p = 100
106.25 - 0.01p = 100
0.01p = 6.25
p = 625
P = 2125 - 625 = 1500

so the amounts were $1500 and $625

Oct 20, 2014 | Mathsoft StudyWorks! Middle School Deluxe...

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Math word problem solver

$15,000 at 3% and $6,000 at 7%.

If this is homework, be sure to show your work.

Sep 06, 2014 | Office Equipment & Supplies

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I want to invest R10000 in a bank investing at 14% compounded twice a year

Invest R10000 in a bank investing at 14% compounded twice a year.

A = P(1+i)^n, where A is the amount, P is the principal or initial investment, i is the interest rate per period, and n is the number of periods.

If the annual rate is 14%, the semi-annual rate is 7%. One year is now composed of 2 6-month periods.

So after one year, we have A = 10 000 (1.07)^2 or 11,449.

Good luck,


Nov 19, 2013 | Sharp EL-738 Scientific Calculator

2 Answers

Examples of independent and dependent variable


for a full definition, try wikipedia.
an independent variable can be freely changed.
a dependent variable will BE changed as the independent variable is changed
basically there are 2 main examples. mathematical, and experimental.

with experiments,(science, chemistry etc.) one example would be changing the amount of fertilizer fed to a plant to see how it affects growth. there are 2 variables here. amount of fertilizer used and growth of the plant.
the amount of the fertilizer can be freely changed. (independent variable)
the amount of growth DEPENDS on the amount of fertilizer (dependent variable)

with maths, you can use something like 2x+5=y.
x can freely changed. it is the independent variable. y will change depending on the value of x.

hope this helps

Jul 04, 2011 | Cycling

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45,000 to invest.want to have 250,000 in 20 years. what rate of interest do i need if its compounding monthly?

4 5 0 0 0 +/- PV (investment amount, negative because you're paying it out)
2 5 0 0 0 0 FV (desired amount, positive because you're receiving it)
2 0 SHIFT xP/YR (20 years)
I/YR (calculate annual interest rate)

Jan 23, 2011 | HP 10bII Calculator

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How to find the best fit for exponential decay?

The error comes from the vanishing values at the tail of the function. The exponential function does not vanish except for -infinity. Truncate the lists by removing the pairs (5,00 and (6,0) or fudge up the data (5, 1E-5) (6,1E-6) and you will get your equation of best fit.

I am including a link to a post of mine where I show how to perform an exponential regression. JUST IN CASE you need additional information on the subject.

Apr 14, 2010 | Texas Instruments TI-84 Plus Calculator

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Mathematical Calculation

Following formula we can use.


EX : (300+x) = x(1+(5.4/100)*1)
(300+x)*100 = 105.4x
x=5555. 4

Jan 05, 2008 | The Learning Company Achieve! Math &...

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Need your help

Try the FV function Syntax

Nov 03, 2007 | Computers & Internet

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