Question about Mathsoft Solving and Optimization Extension Pack III (46513) for PC

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Oct 05, 2016 | Health & Beauty

Let Adjoa's age be x and Kwame's y.

- Adjoa is 3 years older than Kwame: x=y+3
- Seven years ago sum of their ages was 13: (x-7)+(y-7)=13
- Now you substitute first equation into second equation: (y+3-7)+(y-7)=13
- 2y-4-7=13
- 2y=24
- y=24/2=12 years
- x=y+3=12+3=15 years
- sum of their present ages is x+y=12+15=27 years

Sep 27, 2011 | Office Equipment & Supplies

Todd is 4 years old.

Let Tom's age = X

Let Todd's age = Y

From the given facts:

X = 5Y

and

X + 7 + 6 = 3 ( Y + 7 )

X+13 = 3Y + 21

X = 3Y + 8

So if:

X=5Y

and

X=3Y+8

Then:

5Y=3Y+8

2Y=8

Y=4

I hope that helps.

Joe.

Let Tom's age = X

Let Todd's age = Y

From the given facts:

X = 5Y

and

X + 7 + 6 = 3 ( Y + 7 )

X+13 = 3Y + 21

X = 3Y + 8

So if:

X=5Y

and

X=3Y+8

Then:

5Y=3Y+8

2Y=8

Y=4

I hope that helps.

Joe.

Sep 14, 2011 | Office Equipment & Supplies

Correction: **Bob is thrice as old as Peter.**

Let b be the current age of Bob, and p the current age of Peter.**Now, b=3p**

Six years earlier the relations was:**b-6=4*(p-6)=4p-24.**

Take the 6 to the right side leaving b=4p-18

Remember that now b=3p. Use it in the equation above

b=(3p)=4p-18, This becomes 3p=4p-18 or 0=p-18, and**p=18**

**Peter is 18 years old, and Bob is 3*18=54 years old.**

Verification: 6 years ago Peter was 12 years old and Bob 48 years old. 48/12=4.

Let b be the current age of Bob, and p the current age of Peter.

Six years earlier the relations was:

Take the 6 to the right side leaving b=4p-18

Remember that now b=3p. Use it in the equation above

b=(3p)=4p-18, This becomes 3p=4p-18 or 0=p-18, and

Verification: 6 years ago Peter was 12 years old and Bob 48 years old. 48/12=4.

Aug 10, 2011 | Texas Instruments TI-84 Plus Calculator

Nov 09, 2010 | Health & Beauty

X= (1/2)M + 3
2 + X + 20 = M - 6

The father statement is not needed.

Two variables, with two equations. Solve for X.

The father statement is not needed.

Two variables, with two equations. Solve for X.

Sep 29, 2010 | Cameras

Within 11 years, the age of Peter will be half the square of the age he was 13 years ago. Calculate the current age of Peter.

Suzy is ten years older than Billy, and next year she will be twice as old as Billy. How old are they now?

Suzy is ten years older than Billy, and next year she will be twice as old as Billy. How old are they now?

Sep 22, 2010 | Computers & Internet

Three unknowns with three equasions:

cindy is 5 years older than alex. write it as c = a + 5

cindy is 7 years older than peter. write it as c = p + 7

The sum of their ages is 21. write it as c + a + p = 21

first solve for peters age in terms of alex's age.

c = p + 7 or

(a + 5) = p + 7 or

p = (a + 5) - 7 or

p = a - 2

substitute in and solve the equasion:

(a + 5) + a + (a - 2) = 21 or

3a + 3 = 21 or

3a = 24 or

a = 8

c = a + 5 or

c = 8 + 5 = 13

c = p + 7 or

p = c - 7 or

p = 13 - 7 = 6

cindy is 13, alex is 8 and peter is 6

This is called simultaneous equasions and will always work if you have the same number of unknowns as you have equasions (or relationships).

cindy is 5 years older than alex. write it as c = a + 5

cindy is 7 years older than peter. write it as c = p + 7

The sum of their ages is 21. write it as c + a + p = 21

first solve for peters age in terms of alex's age.

c = p + 7 or

(a + 5) = p + 7 or

p = (a + 5) - 7 or

p = a - 2

substitute in and solve the equasion:

(a + 5) + a + (a - 2) = 21 or

3a + 3 = 21 or

3a = 24 or

a = 8

c = a + 5 or

c = 8 + 5 = 13

c = p + 7 or

p = c - 7 or

p = 13 - 7 = 6

cindy is 13, alex is 8 and peter is 6

This is called simultaneous equasions and will always work if you have the same number of unknowns as you have equasions (or relationships).

Sep 20, 2009 | Puzzle Toys

Paul 3 years younger to his friend peter. In seven years, the product of their ages would be 5 more than the product of their ages 5 years ago. How old are they now?

Oct 31, 2008 | Texas Instruments TI-30XA Calculator

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