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Anonymous Posted on Feb 23, 2012
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TI-89 dimension mistmatch error

Differentiate((a*(e^(2x))+b*(e^(3x))*Cos(2x)+c*(e^(3x))*Sin(2x)),x) comes up with Error: Dimension mismatch

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Stevan Milanovic

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  • Posted on Feb 23, 2012
Stevan Milanovic
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Dimension mismatch error occurs when arguments are not with same dimensions. Two or more arguments must be of the same dimension. For example, [1,2]+[1,2,3] is a dimension mismatch because the matrices contain a different number of elements. By the way, it it very easy to resolving your problem with differentiation. See captured image


TI-89 dimension mistmatch error - 2_23_2012_9_41_18_am.jpg

As a result of differentiation you had to obtained:

(3b+2c)cos2x+(3c-2b)(sin2x)e^(3x)+2ae^(2x)

  • 12 more comments 
  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)(sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)(sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)(sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)(sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

  • Stevan Milanovic Feb 23, 2012

    Correction of the result. You had to obtained:

    ((3b+2c)cos2x+(3c-2b)sin2x))e^(3x)+2ae^(2x)

×

1 Related Answer

k24674

  • 8093 Answers
  • Posted on Mar 18, 2011

SOURCE: I try to install software

I do not know the program you installed, so I will skip the part.
As to the derivative of the sine function, your result is correct if the angle unit is degree.
d(sin(x))/dx = cos(x) is true only if the angle unit is the radian. In degrees, you would have a factor Pi/180 which is 0.174532925. I suggest you consult a calculus book to understand where that factor comes from.

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0helpful
1answer

Error Dimension mismatch on ti89
Error Dimension Mismatch:
Two or more arguments must be of the same dimension. For
example, [1,2]+[1,2,3] is a dimension mismatch because the
matrices contain a different number of elements.
Read full answer
Mar 23, 2016 • Texas Instruments TI-89 Calculator
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My TI-30XB WONT CALCULATE INVERSE COS OR INVERSE SIN
Does it refuse to do so or does it give an error message?
Three common errors:
  1. Not having the correct angle unit. Wrong result, No error message
  2. Confusing reciprocal of sine (1/sin(x) with arc sine (x) ,sin^-1(x). Confusing the reciprocal of cosine, 1/cos(x) with arc cosine (cos^-1(x)). Wrong result, No error message
  3. Taking the argument of the inverse sine and/or inverse cosine functions outside the interval [-1,1]. This gives a domain error.
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Oct 28, 2013 • Texas Instruments TI-81 Calculator
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TI-89 dimension mistmatch error

Dimension mismatch error occurs when arguments are not with same dimensions. Two or more arguments must be of the same dimension. For example, [1,2]+[1,2,3] is a dimension mismatch because the matrices contain a different number of elements. By the way, it it very easy to resolving your problem with differentiation. See captured image

2_23_2012_9_31_10_am.jpg

As a result of differentiation you had to obtained:

(3b+2c)cos2x+(3c-2b)(sin2x)e^(3x)+2ae^(2x)

Read full answer
Feb 23, 2012 • Texas Instruments TI-89 Calculator
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1answer

When trying to write simple graph lie Y=x+3 i get err: DIM MISMATCH QUIT
Dimension mismatch error occurs when arguments are not with same dimensions. Two or more arguments must be of the same dimension. For example, [1,2]+[1,2,3] is a dimension mismatch because the matrices contain a different number of elements. By the way, it it very easy to resolving your problem with graphing linear function. See captured image

3_1_2012_9_49_56_pm.jpg
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Sep 22, 2011 • Texas Instruments TI-82 Calculator
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I try to install software on a ti-89 and the dimension error when I open the program. Faso also commonly when derived from sin (x) the result is not cos (x) more so, 0.017 cos (x)
I do not know the program you installed, so I will skip the part.
As to the derivative of the sine function, your result is correct if the angle unit is degree.
d(sin(x))/dx = cos(x) is true only if the angle unit is the radian. In degrees, you would have a factor Pi/180 which is 0.174532925. I suggest you consult a calculus book to understand where that factor comes from.
Read full answer
Mar 17, 2011 • Texas Instruments TI-89 Calculator
1helpful
3answers

TI89 is giving wrong answer for the integral of sec(x). Please help. It gives the answer as: ln[ |cos(x) / (sin(x)-1)| ] when it should be ln[ |(sin(x)-1) / cos(x)| ]. Why is it giving the wrong...
Hi danagasta,

If my last instructions did not work then you need to reset your RAM. You are missing the negative sign and, I have no idea where you got the absolute value inside the brackets.
Yes, the absolute value are used in books and, on integral tables but, I can asure you that the Ti 89 should not have produce them in this answer.

I'll stand behind that In( -cos(x) / (sin(x)-1)) is the correct answer. You can go ahead and simplify after the calculation to get the answer you want but, that is the good answer that Ti 89 is going to give you for the integral of sec(x).

Errors that do not match the suspected, I am pretty sure that Texas Instruments would have you clear the RAM. I do not like resetting the RAM but, I could not find the cause to why you got the answer you did. And so far no other expert has produced a solution to convince me otherwise.

I was not able to come up with any of the 3 answers MiB8888 did on my Ti 89. I am not saying that they are not good answers, they are book and integral tables answers. You are not going to get them on the Ti 89.

Read full answer
Jan 04, 2011 • Texas Instruments TI-89 Calculator
0helpful
1answer

Differentiate each of the following w.r.t.x; 29.sin2xsinx
Use the rule for differentiating products of functions: ()' signifies derivative
(29*sin(2X)*sin(X))'= (29)'*sin(2X)*sin(X) +29* (sin(2X))'*sin(X) +29*sin(2X)*(sin(X))'
But
  1. (29)'=0 derivative of a constant is zero
  2. (sin(2X))'=cos(2X)*(2X)'=2*cos(2X)
  3. (sin(X))'=cos(X)
Result is
(29*sin(2X)*sin(X))'= 29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)

You could also have cast your formula in the form
sin(2X)*sin(X)= 1/2[ cos(2X-X)-cos(2X+X)]=1/2[cos(X)-cos(3X)]
then calculated the derivative of
29/2*[cos(X)-cos(3X)]
which is
29/2*[-si(X) +3*sin(3X)]

The challenge for you is to prove that the two forms are equivalent
29*2*cos(2X)*sin(X)+29*sin(2X)*cos(X)=29/2*[-si(X) +3*sin(3X)]

Read full answer
Jun 21, 2010 • Vivendi Excel@ Mathematics Study Skills...
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For ti 84+ HOW do I solve the error indication
Certain mathematical entities have so called dimensions: A list has a dimension, which is the number of elements in the list. Matrices also have dimensions which are the number of rows, and the number of columns.

If you are doing paired variable statistics, the data is in two lists and if the number of elements in one list is not equal to the number of elements of the the other, the dimension are not matched (equal), and calculator will give you dimension mismatch in any calculation that involves BOTH list.

The problem with your question is that you do not say what you were trying to do and I will have to guess or read your mind.

I suggest you reset the RAM to erase any old configuration that may be interfering with what you want to do.
  1. Press [2nd] [+] to access (MEM)ory management.
  2. Press [7:Reset][1:All ram][2:Reset]
  3. Calculator answers with "Ram Cleared" message.
  4. Press [CLEAR] to erase the message.
  5. Restart what you were doing (statistics, or graphs)
Read full answer
Jun 19, 2010 • Texas Instruments TI-84 Plus Calculator
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TI-89 Titanium Dimension Error
The folder your operating from could cause you problems. To integrate, I usually do that in the main folder, and I make sure I have all my variables deleted before I begin. The owners manual say under Dimension error is because of different sizes of lists, and that would be caused by undeleted variables.


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Feb 05, 2009 • Texas Instruments TI-89 Calculator
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Help
sec^4X- sec^2X = 1/cot^4X + 1/cot^2X
RHS
1/cot^4X + 1/cot^2X
=1/(Cos^4X/Sin^4X) + 1/(Cos^2X/Sin^2X)
=Sin^4X/Cos^4X + Sin^2X/Cos^2X
=Sin^4X/Cos^4X + Cos^2X.Sin^2X/Cos^4X
=Sin^2X/Cos^4(Sin^2X + Cos^2X)
=Sin^2X/Cos^4X
=(1-Cos^2X)/Cos^4X
=1/Cos^4X - Cos^2X/Cos^4X
=1/Cos^4X - 1/Cos^2X
=Sec^4X - Sec^2X
=LHS
Read full answer
Feb 02, 2009 • Super Tutor Trigonometry (ESDTRIG) for PC
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