Could someone please help me on how to name the equations so that I dont have to scroll looking for the equation by just seeing the equations inputs, I want to save serveral equations and organize them by name so when I look for the equation I can find it by looking at the name.

Thx

Naming the equation via MY_NAME:ABC=0*L(A:blah blah and so on) will help somewhat, but if you want to search for the equation by your assigned name, you are out of luck, that functionality is not there. The best you can do is SAVE your equations in alphabetical order (by name) by creating the new equation at the right place in your sequence of equations. Then you can get to the beginning of the list by (gold or blue, depending upon which version of the 17bii+ you have) up-arrow, and down-arrow for the end of the list. It would be great if you could search for the name, but HP has not included that functionality.

Don

Posted on Dec 22, 2008

Use the colon

EQUATIONNAME: EQUATION

Posted on Nov 07, 2008

Sorry to be frank about it, but your sentence ..**I dont want to have to read something that looks like it was typed in a forien language!!** is not flawless English.

Be it as it may, here is how you solve**most,** if not all, **high school algebraic equations.**

The secret is in the use of the mnemonic known as PEDMAS, or BEMDAS, which lists the priority of operations. USE IT BACKWARDS, and recursively (look up this word in an English dictionary).

*Basically one tries to use PEDMAS in reverse, identifying each operation and doing the inverse of it. If you have an addition, do a subtraction. If you have a multiplication, do a division. If you have a power, extract the root, and if you have a root raise to the corresponding power. *

When the factor to the left of parentheses is +1**(if nothing appears it is +1) **you can safely discard the parentheses.

After opening parentheses start again A/S then D/M, then Exponent/roots, parentheses, etc...**until the unknown sits by itself on one side of the equal sign.**

I hope that my English does not sound too much like a foreign language to you**. **I did my best because English is my third language.

Be it as it may, here is how you solve

The secret is in the use of the mnemonic known as PEDMAS, or BEMDAS, which lists the priority of operations. USE IT BACKWARDS, and recursively (look up this word in an English dictionary).

- Starting from the end of the mnemonic (A or S) look for a minus sign or a plus sign. Here you have 4-12, the result is -8.
- Your expression is equivalent to -8 -(X+3)=10
- To get rid of the -8 term on the left ADD +8 to BOTH sides of the equation and simplify. -8+8-(X+3)=10+8=18 or simpler still -(X+3)=18
- A minus sign in front of the parenthesis is in fact a multiplication by -1. Get rid of this factor : It is safer to get rid of the - sign in front of the parenthesis by multiplying BOTH sides of the equation by (-1). This gives you (X+3)=-18.
**MINUS signs are always signs of DANGER, to be handled with care.**

- Now you can safely open the parentheses: X+3=-18
- You have an addition in the left member. To isolate X, perform the operation that is inverse of addition, namely subtraction. Subtract 3 from both sides of the equation: X+3-3=-18-3, or
**X=-21** - X is isolated, and your equation is solved.

When the factor to the left of parentheses is +1

Sep 30, 2014 | Calculators

Enter the equation as 2*X+3. Make sure that the name of the independent variable X in the equation and that on the INDEP:X line are both Capital letters or both lowercase letters.

Aug 28, 2013 | HP 48gx Calculator

There is no equation solving mode (utility) on this calculator. Sorry.

Apr 06, 2013 | Casio FX82MS Scientific Calculator

Most probable that you are not using the correct syntax.

Press MATH, then scroll down to reach the SOLVER line. Press ENTER. Create the equation, using the ALPHA keyboard to type in letter symbols.

Press ENTER. The screen that opens displays the equation and a list of the variable present in your equation. Each letter (variable) must have a value, except the unknown. If there is a 0 after the = sign on the same line as the unknown, you must clear it so as to leave a blank.

Specify the lower bound and the upper bound to speed up the search.

Once finished press [ALPHA][ENTER] to execute the (SOLVER)

Press MATH, then scroll down to reach the SOLVER line. Press ENTER. Create the equation, using the ALPHA keyboard to type in letter symbols.

Press ENTER. The screen that opens displays the equation and a list of the variable present in your equation. Each letter (variable) must have a value, except the unknown. If there is a 0 after the = sign on the same line as the unknown, you must clear it so as to leave a blank.

Specify the lower bound and the upper bound to speed up the search.

Once finished press [ALPHA][ENTER] to execute the (SOLVER)

Oct 20, 2011 | Texas Instruments TI-83 Plus Calculator

Press the Y= button.

There are several possibilities:

1) Scroll through all equations, Y1 through Y9 and Y0. Make sure they are cleared.

2) The equation you typed in is not entered correctly.

3) Make sure Plot 1, Plot 2, and Plot 3 are NOT highlighted.

There are several possibilities:

1) Scroll through all equations, Y1 through Y9 and Y0. Make sure they are cleared.

2) The equation you typed in is not entered correctly.

3) Make sure Plot 1, Plot 2, and Plot 3 are NOT highlighted.

Feb 01, 2011 | Texas Instruments TI-84 Plus Calculator

This expression 5x^2+15x+3 is not an equation, therefore it can have any value depending on the value of x. You have to make it an equation before looking for the particular value of x that satisfy your equation **5x^2+15x+3 =0**

This calculator cannot solve equations because it does not have an equation solver.

This calculator cannot solve equations because it does not have an equation solver.

Dec 15, 2010 | Sharp ELW535 Calculator

"Is there anything that I can do about this to stop my answers being complex numbers when solving cubic equations?"

You are making an assumption that is unwarranted.Namely that a cubic equation must necessarily have 3 real roots. This is not the case.

Let your equation be

If coefficients are complex you should expect some complex roots. Right?

If the coefficients are REAL then depending on the discriminant

you can have three cases

DELTA positive : three distinct real roots

DELTA=0 , the equation has a multiple root and all roots are REAL

DELTA negative: the equation has ONE real root and 2 complex roots that are complex conjugate of each other.

It suffices to look at the Tartaglia/Cardano expressions of the roots to know that more often than not there is going to be complex roots.

You are making an assumption that is unwarranted.Namely that a cubic equation must necessarily have 3 real roots. This is not the case.

Let your equation be

If coefficients are complex you should expect some complex roots. Right?

If the coefficients are REAL then depending on the discriminant

you can have three cases

DELTA positive : three distinct real roots

DELTA=0 , the equation has a multiple root and all roots are REAL

DELTA negative: the equation has ONE real root and 2 complex roots that are complex conjugate of each other.

It suffices to look at the Tartaglia/Cardano expressions of the roots to know that more often than not there is going to be complex roots.

May 05, 2010 | Casio CFX-9850G Plus Calculator

Hello,

I will not ask what you want to do with the equation I will answer your question about the equal sign. Press [2nd][CATALOG] you access the catalog of available commands. The equal sign is near the bottom of the list. So it is faster to scroll up from the top, and keep scrolling up till you reach the =. Select it and press [ENTER], it will echoe at the place where the cursor was before you press [2nd][CATALOG]. Complete your equation.

Hope it helps.

I will not ask what you want to do with the equation I will answer your question about the equal sign. Press [2nd][CATALOG] you access the catalog of available commands. The equal sign is near the bottom of the list. So it is faster to scroll up from the top, and keep scrolling up till you reach the =. Select it and press [ENTER], it will echoe at the place where the cursor was before you press [2nd][CATALOG]. Complete your equation.

Hope it helps.

Oct 21, 2009 | Texas Instruments TI-84 Plus Calculator

Hello,

Sorry, but what you wrote is not an equation but a polynomial expression. You want to solve the equation x^4+5x^3-3x^2-43x-60 =0.

The solve( command, can only be used with real numbers.

The** solve(** is available through the CATALOG :
[2nd][CATALOG], scroll down till you reach the command. Highlight it
and press [ENTER]. The command echodes on main screen as **solve(** .

You complete the command by entering the expression (not the equation), the name of the variable you solve for, the initial guess , and { lower limit, upper limit} between curly brackets, and the closing parenthesis.

Exemple:

**solve (x^4+5x^3-3x^2-43x-60 ****, x,0 {-5,0} ) [ENTER]**

should give you the negative root,

**solve (x^4+5x^3-3x^2-43x-60 ****, x,0 {0,5} ) [ENTER]**

should give you the positive root.

It is implied that the expression is 0, so you should not insert =0, otherwise you get an error. Here for the lower limit is -5 you must use the change sign symbol (-) under the 3 key, not the regular MINUS.

You may ask how I knew that there were two roots when the equation is a quartic? By first graphing it to have an idea about where the roots lie and how many there are. You should always do that to speed up the search.

There is another way to zoom in on the roots: by drawing the graph and using the tools accessible under the [2nd][CALC] menu, namely the option [2:Zero]

The resolution of the TI83/84 is not good enough for this function that grows too fast, but I am inserting a picture of the curve from another calculator with a much better resolution.

Hope it helps.

Sorry, but what you wrote is not an equation but a polynomial expression. You want to solve the equation x^4+5x^3-3x^2-43x-60 =0.

The solve( command, can only be used with real numbers.

The

You complete the command by entering the expression (not the equation), the name of the variable you solve for, the initial guess , and { lower limit, upper limit} between curly brackets, and the closing parenthesis.

Exemple:

should give you the negative root,

should give you the positive root.

It is implied that the expression is 0, so you should not insert =0, otherwise you get an error. Here for the lower limit is -5 you must use the change sign symbol (-) under the 3 key, not the regular MINUS.

You may ask how I knew that there were two roots when the equation is a quartic? By first graphing it to have an idea about where the roots lie and how many there are. You should always do that to speed up the search.

There is another way to zoom in on the roots: by drawing the graph and using the tools accessible under the [2nd][CALC] menu, namely the option [2:Zero]

The resolution of the TI83/84 is not good enough for this function that grows too fast, but I am inserting a picture of the curve from another calculator with a much better resolution.

Hope it helps.

Oct 18, 2009 | Texas Instruments TI-83 Plus Calculator

I assume you are speaking of solving a system of equations with a number of unknowns. If not, please correct me. Here's an example in practice:

If you have a system of 3 equations with 3 unknowns, you would set up your matrix so that the coefficients of each variable for a particular equation are on one row. So, given equations x + y + z = 0, 2x + 3y - 4z = 1, x + -z = -1 you would type the following into your calculator: [[1,1,1,0][2,3,-4,1][1,0,-1,-1]] and press enter to make sure you typed it correctly. notice that in the third row there is a zero, since we have zero time y for the third equation. Then row-reduce the matrix (2nd > 5 > 4 > 4 or in the CATALOG as rref). You should get out the matrix [[1,0,0,-1][0,1,0,1][0,0,1,0]]. This says that x=-1 y = 1 z=0 since my first column contained the coefficients for the x variable, the second for the y variable, and the third for the z variable. The last column contains the solution, the part on the other side of the equals sign.

Hope this helps! For more reading (from someone else; I just made this one up), check out the Wikipedia articles on Gaussian elimination and Systems of linear equations

If you have a system of 3 equations with 3 unknowns, you would set up your matrix so that the coefficients of each variable for a particular equation are on one row. So, given equations x + y + z = 0, 2x + 3y - 4z = 1, x + -z = -1 you would type the following into your calculator: [[1,1,1,0][2,3,-4,1][1,0,-1,-1]] and press enter to make sure you typed it correctly. notice that in the third row there is a zero, since we have zero time y for the third equation. Then row-reduce the matrix (2nd > 5 > 4 > 4 or in the CATALOG as rref). You should get out the matrix [[1,0,0,-1][0,1,0,1][0,0,1,0]]. This says that x=-1 y = 1 z=0 since my first column contained the coefficients for the x variable, the second for the y variable, and the third for the z variable. The last column contains the solution, the part on the other side of the equals sign.

Hope this helps! For more reading (from someone else; I just made this one up), check out the Wikipedia articles on Gaussian elimination and Systems of linear equations

May 03, 2009 | Texas Instruments TI-84 Plus Calculator

Feb 22, 2009 | HP 17bII+ Calculator

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