Question about Natural Science Industries Dolls, Playsets & Toy Figures
Can you tell me the safest way to dispose of this partially-used chemistry set? The set is several years old, but there are still chemicals in many of the vials. Thank you.
Contact your local waste plant. The place where you would drop off old unusable items like old mattresses, etc.aka The Dump. They have an area for hazardous waste like old paints, etc. This would be the place to drop it off. I know in our area, they do not charge to drop off old oil, paints, etc. as you are doing the right thing for the environment by not sticking it in the trash.
Good Luck! from Moms Just Know
Posted on Oct 24, 2008
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The calculated moles of C = [grams C] / [MW of C] = [188 g C / 12.0 g] = 15.7 mol C
Therefore, there are 15.7 moles of O2, as calculated from use of the math expression (with boxes) shown above.
The wanted GRAMS of O2 are calculated from MW of O2 times its number of moles, as follows:
Grams of O2 = 32.0 g O2 x 15.7 mol O2 = 502 grams O2.
For your convenience as you make conversions among grams and moles, you may use the following memory aid:
To go from moles to grams, just notice that moles are beside MW, so multiplying them will give grams (moles x MW = grams). If you want to go from grams to moles, notice that grams are over MW, so (grams/MW) = moles. If you should want to calculate MW, you would divide grams by moles, (grams/moles) = MW.
One more tip: When doing calculations, use at least the same number of significant figures (sig figs) in the molecular weights (and atomic weights) as is in the given numerical data. That is, since there are three sig figs in 188 grams of C, use 12.0 as the atomic weight of C, and 44.0 as the MW of CO2. You would obtain the same answer using 12 and 44, but as you may know, following this rule would be more important in other problems in which the digit past the decimal is not zero. This allows proper rounding off of the final calculated quantity.
Suggestion: Try out this method to other problems involving a chemical reaction. Good luck!
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