I entered the integrand symb, then (SQRT((r^2)-(y^2))),y,0,r) and came up with the "too few arguments" error. This happens regularly but not always when I integrate. Any suggestions/

I reset my calculator and this solved the problem. To reset your calculator press [2nd], then [6] (Mem), press F1 (reset), Select 3 for all memory, and select Yes.

Posted on Nov 26, 2008

**Too few arguments **error occurs when expression or equation is missing one or more arguments. For example, d(f(x)) is invalid; whereas, d(f(x),x) is the correct syntax.By the way it is very easy to resolving this integral problem. See cap image

Posted on Mar 03, 2012

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Posted on Jan 02, 2017

There are several ways of doing this.

Since you're using a graphing calculator, you can always graph it as a function of 'a' and use the graphical tools.

Another way is to use the solve() function. For example, to find the value of a where the integral of sin(x) from 0 to a equals one, enter

solve(fnInt(sin(X),X,0,A)-1),A,1.5)

solve( and fnInt( are accessible through the CATALOG. The 1.5 is an initial guess.

Since you're using a graphing calculator, you can always graph it as a function of 'a' and use the graphical tools.

Another way is to use the solve() function. For example, to find the value of a where the integral of sin(x) from 0 to a equals one, enter

solve(fnInt(sin(X),X,0,A)-1),A,1.5)

solve( and fnInt( are accessible through the CATALOG. The 1.5 is an initial guess.

Apr 19, 2014 | Texas Instruments TI-84 Plus Silver...

Set Input/output to MathIO.

Press the Integrate key, to the right of CALC.

The image of integral appears with a rectangle for the function, and two small squares (one for the upper limit the other for the lower limit).

Type in the integrand (the expression you want to integrate) in the bigger (on your display) rectangle. Use appropriate parenthesis. To type in X press [ALPHA] )

Use the down arrow to move cursor to the square for the lower limit. Type in the lower limit. Use the Up arrow to move cursor to the upper limit square. enter the upper limit. Press [=] key. If you did not make mistakes, and your expression is not too complicated you should get your integral.

Note: The screen captures are not from a Casio FX991ES. But that should not matter to you.

Press the Integrate key, to the right of CALC.

The image of integral appears with a rectangle for the function, and two small squares (one for the upper limit the other for the lower limit).

Type in the integrand (the expression you want to integrate) in the bigger (on your display) rectangle. Use appropriate parenthesis. To type in X press [ALPHA] )

Use the down arrow to move cursor to the square for the lower limit. Type in the lower limit. Use the Up arrow to move cursor to the upper limit square. enter the upper limit. Press [=] key. If you did not make mistakes, and your expression is not too complicated you should get your integral.

Note: The screen captures are not from a Casio FX991ES. But that should not matter to you.

Feb 10, 2014 | Casio FX991ES Scientific Calculator

Unfortunately this calculator does not display results in radical form. If you enter SQRT(147) you get 12.12435565...

What you are asking for is called**rationalizing** an irrational expression. Usually one tries to get rid of radicals that appear in the denominators. Here is an example.

Suppose you have 1/(c+SQRT(d)), and you want to get rid of the radical in the denominator. How to do it?

Recall the identity** (a-b)*(a+b)= a^2-b^2**. It is true for any **a** and **b **

**Rationalizing a denominator** (usual case)

Now consider (c+SQRT(d)). Multiply it by (c-SQRT(d))

[c+SQRT(d)]*[c-SQRT(d)]=c^2 -[SQRT(d)]^2=**c^2-d**

You see that there is no radical.

Now take**1/(c+SQRT(d))**. To get rid of the radical from the denominator multiply it by (c-SQRT(d)). But to leave the value of your expression ** 1/(c+SQRT(d))** unchanged, you must multiply both numerator and denominator by (c-SQRT(d)).

The numerator becomes 1*(c-SQRT(d))=**c-SQRT(d)**, and the denominator **(c^2-d)**.

Finally, the rationalized form of the expression**1/(c+SQRT(d))** is

[**c-SQRT(d)**]**/[c^2-d]**.

**Rationalizing a numerator**

Sometimes, people have a radical in the numerator that they want to get rid of and have it in the denominator. The procedure is the same

Example:**(c+SQRT(d))**, the denominator here is 1

**(c+SQRT(d))**=(c+SQRT(d))*[c-SQRT(d)]/[c-SQRT(d)]. This gives

**[c^2-d]/[c-SQRT(d)]**

You have no radical in the numerator but there is one in the denominator. This is called rationalizing the numerator.

Your case is a lot simpler

SQRT(147)=7*SQRT(3)

Multiply it by SQRT(3)/SQRT(3) which is 1. This gives

SQRT(147)=7*3/SQRT(3)=21/SQRT(3)

**SQRT(147)= 21/SQRT(3)**

What you are asking for is called

Suppose you have 1/(c+SQRT(d)), and you want to get rid of the radical in the denominator. How to do it?

Recall the identity

Now consider (c+SQRT(d)). Multiply it by (c-SQRT(d))

[c+SQRT(d)]*[c-SQRT(d)]=c^2 -[SQRT(d)]^2=

You see that there is no radical.

Now take

The numerator becomes 1*(c-SQRT(d))=

Finally, the rationalized form of the expression

[

Sometimes, people have a radical in the numerator that they want to get rid of and have it in the denominator. The procedure is the same

Example:

You have no radical in the numerator but there is one in the denominator. This is called rationalizing the numerator.

Your case is a lot simpler

SQRT(147)=7*SQRT(3)

Multiply it by SQRT(3)/SQRT(3) which is 1. This gives

SQRT(147)=7*3/SQRT(3)=21/SQRT(3)

Feb 09, 2014 | Texas Instruments TI-30XA Calculator

The calculation may be taking too long and you got impatient. To reduce the time it takes to calculate some expression or find a root you can make better guesses (initial values), or choose better limits to an integral, or divide the integral in two if integrand symmetrical. If you can select the tolerance (error you are willing to accept), increase it: Instead of taking epsilon =1E-9, take epsilon=1.E-5. But that depends on the context of the calculations. You be the judge.

Nov 27, 2013 | Casio Fx-991es Scientific Calculator

If you're in the MATHPRINT mode, press

2ND [COS^-1] ( 8 - 3 2ND [sqrt] 2 1 right-arrow ) / 2 5 ENTER

If you're in the CLASSIC mode, press

2ND [COS^-1] ( 8 - 3 2ND [sqrt] 2 1 ) ) / 2 5 ENTER

In either case you should get an answer of about 103.

2ND [COS^-1] ( 8 - 3 2ND [sqrt] 2 1 right-arrow ) / 2 5 ENTER

If you're in the CLASSIC mode, press

2ND [COS^-1] ( 8 - 3 2ND [sqrt] 2 1 ) ) / 2 5 ENTER

In either case you should get an answer of about 103.

Apr 27, 2013 | Texas Instruments TI-84 Plus Calculator

The error data type means that the program is expecting a specific type of data ( number, list, matrix, real, complex, string, etc.) while you are feeding it some other type of data. The point in the program where you are taken when the error occurs is where the exception was launched.

A common source of error stems from the use of variables that are global and defined in some other program. You can use the same name inside your program as long as you declare the variable local.

If your program is in fact a function, then all its argument must be passed in the call to the function: You cannot ask a function to read your input.

I will not pretend to know why you get the error, but the few comments I made above may help you debug the program.

By the way, if you are interested a Cobebrook online calculator, here is a link

A common source of error stems from the use of variables that are global and defined in some other program. You can use the same name inside your program as long as you declare the variable local.

If your program is in fact a function, then all its argument must be passed in the call to the function: You cannot ask a function to read your input.

I will not pretend to know why you get the error, but the few comments I made above may help you debug the program.

By the way, if you are interested a Cobebrook online calculator, here is a link

Apr 26, 2011 | Texas Instruments TI-89 Calculator

You can perform coordinate conversions in the COMP, STAT, MATRIX and VECTOR Modes.

Angle unit may be in either degree or radian.

To convert from rectangular to polar, (SQRT(2)/2,SQRT(2)/2)

Press [SHIFT] [+] (Pol)

Screen displays Pol(

Type in SQRT2

Use right arrow to move cursor out of radical

Type in /2 [SHIFT] [,]

Type in SQRT2

Use right arrow to move cursor out of radical

Type in /2

Close the right parenthesis

Screen displays Pol (SQRT2 /2, SQRT2 / 2)

Press [=]. Display echoes the command on top line and result in bottom line as r=1, theta =45, (if unit is in degree) or theta = 0.7853981634 if unit is radian.

To convert from polar to rectangular coordinates

Note: You cannot use the answer memory to convert back to rectangular because the calculator will use the r-value only. So you will have to enter the radius AND the angle.

ex: Rec(1,45)

Angle must be in degree

Press [SHIFT][-] (Rec)

Screen display Rec(

Type in 1 [SHIFT] (,) 45 [)] [=]

Calculator displays X=0.7071067812, Y=0.7071067812

If you press the SD key hoping to convert the decimals to radicals, the calculator will not do it.

As to the "confusion", I have found none.

After you finish entering the argument of a square root, use the right arrow to move cursor out of under the root symbol to signify that the argument is complete. If you use a left parenthesis inside the root, you must insert the matching right parenthesis inside the root, then move cursor outside the root.

This is how the calculator behaves, and I am not expressing an opinion on how simple or complicated that is. I assume that to make full use of the calculator capabilities, one has to converse with it, using the syntax it understands.

Angle unit may be in either degree or radian.

To convert from rectangular to polar, (SQRT(2)/2,SQRT(2)/2)

Press [SHIFT] [+] (Pol)

Screen displays Pol(

Type in SQRT2

Use right arrow to move cursor out of radical

Type in /2 [SHIFT] [,]

Type in SQRT2

Use right arrow to move cursor out of radical

Type in /2

Close the right parenthesis

Screen displays Pol (SQRT2 /2, SQRT2 / 2)

Press [=]. Display echoes the command on top line and result in bottom line as r=1, theta =45, (if unit is in degree) or theta = 0.7853981634 if unit is radian.

To convert from polar to rectangular coordinates

Note: You cannot use the answer memory to convert back to rectangular because the calculator will use the r-value only. So you will have to enter the radius AND the angle.

ex: Rec(1,45)

Angle must be in degree

Press [SHIFT][-] (Rec)

Screen display Rec(

Type in 1 [SHIFT] (,) 45 [)] [=]

Calculator displays X=0.7071067812, Y=0.7071067812

If you press the SD key hoping to convert the decimals to radicals, the calculator will not do it.

As to the "confusion", I have found none.

After you finish entering the argument of a square root, use the right arrow to move cursor out of under the root symbol to signify that the argument is complete. If you use a left parenthesis inside the root, you must insert the matching right parenthesis inside the root, then move cursor outside the root.

This is how the calculator behaves, and I am not expressing an opinion on how simple or complicated that is. I assume that to make full use of the calculator capabilities, one has to converse with it, using the syntax it understands.

Mar 31, 2010 | Casio FX-115ES Scientific Calculator

Hello,

The default variable for the integral is x. If you have a product between two litteral symbols the * must be inserted. Arguments of functions must be enclosed between parentheses. To avoid errors clear the variables before the integration: [2nd][F6:Clean Up] [2:NewProb][ENTER]ENTER]

Hope it helps.

The default variable for the integral is x. If you have a product between two litteral symbols the * must be inserted. Arguments of functions must be enclosed between parentheses. To avoid errors clear the variables before the integration: [2nd][F6:Clean Up] [2:NewProb][ENTER]ENTER]

Hope it helps.

Sep 30, 2009 | Texas Instruments TI-89 Calculator

Hello,

Here is a screen capture of the integral.

The dummy variable x may contain some previously defined value. Clear old values . In Home folder [2nd][F6: Clean Up][ 1:Clear a-z] [ENTER][ENTER] or [2:NewProb][ENTER][ENTER]

Make sure you insert the multiplication sign. And do not forget to put the argument x of the function inside parentheses.

Hope it helps.

Here is a screen capture of the integral.

The dummy variable x may contain some previously defined value. Clear old values . In Home folder [2nd][F6: Clean Up][ 1:Clear a-z] [ENTER][ENTER] or [2:NewProb][ENTER][ENTER]

Make sure you insert the multiplication sign. And do not forget to put the argument x of the function inside parentheses.

Hope it helps.

Sep 30, 2009 | Texas Instruments TI-89 Calculator

Hello,

You should enter it as follows [SQRT]36 ) [ENTER/=].

If you define some function f of a variable x you write that f(x), where the parentheses enclose the so-called argument (objet on wich the function acts). It seems that on this calculator the opening parenthesis is implicit: the calculator supplies it when you press [SQRT] but does not display it (a design flaw?). However the closing parenthesis must be entered by you to signifie to the function [SQRT] that you have finished entering the argument. Weird but one can live with it.

Hope it helps.

You should enter it as follows [SQRT]36 ) [ENTER/=].

If you define some function f of a variable x you write that f(x), where the parentheses enclose the so-called argument (objet on wich the function acts). It seems that on this calculator the opening parenthesis is implicit: the calculator supplies it when you press [SQRT] but does not display it (a design flaw?). However the closing parenthesis must be entered by you to signifie to the function [SQRT] that you have finished entering the argument. Weird but one can live with it.

Hope it helps.

Oct 19, 2008 | Texas Instruments TI-15 Explorer...

May 21, 2014 | Texas Instruments TI-89 Calculator

Feb 17, 2014 | Texas Instruments TI-89 Calculator

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Usually answered in minutes!

Same here. It's whenever I integrate. I even tried the example provided in the TI booklet! Didn' t work?

that error pops up on mine frequently. I also tried to solving problems out of the book and had no luck figuring it out.

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