# Using logs How do you use the calculator with this problem What is the real value of x in the equation log^2 24 - log^2 3 = log^5 x

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log x base y = log x / log y
log (x*y) = log x + log y
log (x/y) = log x - log y

so log 24 base 2 it's log 24 / log 2 etc.
and if i get right what you wrote x= 10 ^ ( 3 * (log 5) ) if no inverse it it's easy really Hope it's helped you.

Posted on Jul 06, 2009

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Posted on Jan 02, 2017

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## Related Questions:

### Logbase16xtopower5=logbase64 125-logbase4rootx soveforx

Type solve(log(x^5,16)-log(125,64)+log(x^(1/2),4),x,0.5
Its equation with guess 0,5. Then press enter and you will give result
x=5^(1/3)=1.70997
Or, you can use equation solver with eqn=0(MATH, then B option)
See captured images below

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### How to find values of x in higher order equations(above cube) on casio 570 ES?

In equation mode, you have system of linear equations (3 unknown) you have polynomial (quadratic and cubic), and solver. Use the solver foe any type of equation (nonlinear, polynomial of order higher than 4, trigonometric, exponential, logs).

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### Finding value of log with base 10

Use the "log" key. For example, to calculate the log base 10 of 2, press
"log" "2" =

Mar 29, 2012 | Casio FX991ES Scientific Calculator

### If an equation would require dividing by log ( which og course can't be done) what button is used to fulfil that equation?

Of course you can divide by a log. As an example, to divide 2 by the log of 3, press
2 / 3 LOG =
To divide 2 by the natural log of 3, press
2 / 3 LN =

Oct 27, 2011 | Texas Instruments TI-30XA Calculator

### When I go to use the 'log' button on TI 30XA I do not come up with the same answer as in my course book (for the examples) No real instructions on logs in the little instruction book. Have tried...

You calculate the pH with the relation
pH=-log(c) where c is the value of concentration in mol/L.
ex: c[H+]= 3.57x10^(-6)
pH: (-) [LOG] 3.57 [2nd][EE] [(-)] 6 [ ) ]
Here you have 2 change sign key press [(-)]

If you have the pH, and want to calculate the concentration that yields that value of the pH you proceed as follows
c= 10^(-pH)
Ex pH=8.23
c: [2nd][LOG] [(-) 8.23 [)]

General shortcut.
If concentration is of the form c[H+]= 1*10^(-a) where a is an integer between 0 and 14, the pH is equal to the positive value of exponent.

Ex:c[H+]=1x10^(-5) Mol/L then the pH is just the positive value of the exponent, ie 5 because pH=-log(1.x10^-5) =- log1 -log(10^-5)=0 -(-5)=5
Above I use the rule log(axb)=log(a)+log(b) , the rule log(a^b) = b*log(a)and the facts that log(1)=0 and log(10)=1, the last being true if log stands for log in base 10.

May 17, 2011 | Texas Instruments TI-30XA Calculator

### How do I enter in equations with logarithms that have bases other than 10 or e?

If you want to take the log of X using base B, where B is an arbitrary number, use the following equation:

logB(X) = log10(X) / log10(B)

In words this is the log base B of X equals the log base 10 of X divided by the log base 10 of B. This equation can now be solved using your calculator.

I hope this helps you out.

Feb 09, 2011 | Vacuums

### How do you enter a logarithmic equation into my calculator?

The 30XIIS does not have the capability of solving equations. It can, however, calculate expressions using logarithms. Use the LOG key for common logarithms and the LN key for natural logarithms. In both cases, press the function key, enter the value or expression, and then ) to match the ( the function automatically enters.

The LOG and LN keys are the second and third keys from the top in the leftmost column of the keyboard.

Nov 13, 2010 | Office Equipment & Supplies

### Log4 (x+1) + log4 (x-2) =1

This is not a calculator problem. Use the rules you have learned to simplify your problem.
For a a log in any base. log(a*b) =log(a) +log(b) or log(a)+log(b) =log(a*b).
Thus
log(x+1)+log(x-2)= log[(x+1)*(x-2)]=1
Use the fact that log4=log in base 4 and rewrite the equation with the appropriate symbols. log4[(x+1)*(x-2)] =1
However 1=log4(4) and
log4[(x+1)*(x-2)]=log4(4)
The equality of the two logs implies the equality of their arguments (contents) and

(x+1)*(x-2) =4

Now you solve this quadratic equation by the methods you must have learned (sorry I have to leave some thing for you to do, to ensure that proper learning is achieved).
Once you find the roots of the quadratic equation, verify that each term in your original expression has meaning-- x+1 positive and x-2 positive.

If one of the roots makes the argument (x+1) or (x-2) negative, reject it. because the argument of a log function cannot be negative.

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### How to calculate log value in calculator with different base value

In any scientific calculator log2(n) can be  calculated with either ln or log function as follows

Log2(n)= ln(n) / ln(2)

Or
Log2(n)=log(n) / log(2)

both will give nearly the same answers

Dec 08, 2007 | Casio FX-300MS Calculator

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