Question about SoftMath Algebrator - Algebra Homework Solver (689076614429)

512x^6-1/216

512x^6 -1/216 can be factored to (8x^2 - 1/6)^3

Proof

(8x^2 - 1/6)(8x^2 - 1/6) = 64x^4+ 1/36

(64x^4+ 1/36)(8x^2 - 1/6) = 512x^6 - 1/216

Hope this helps

Good luck Loringh

Posted on Oct 18, 2008

The best known irrational number is Pi, so, any formula with that in it it, like the formula for

circumference of a circle - Pi * D

area of a circle - Pi * R^2

volume of a sphere - 4/3 * Pi * R^3

Here D and R should be rational numbers, eg integers, to meet your definition.

circumference of a circle - Pi * D

area of a circle - Pi * R^2

volume of a sphere - 4/3 * Pi * R^3

Here D and R should be rational numbers, eg integers, to meet your definition.

Dec 02, 2014 | Educational & Reference Software

The domain and the range are both all nonnegative real numbers.

May 08, 2014 | SoftMath Algebrator - Algebra Homework...

1st and 3rd although negative volume makes no sense in the 3rd quadrant

Apr 11, 2014 | Educational & Reference Software

The first. The pure function V(s)=s^3 is in the first and third, but it does not make sense to have a negative value for s.

Sep 24, 2013 | SoftMath Algebrator - Algebra Homework...

Here, We deal with Some Special Products in Polynomials.

Certain products of Polynomials occur more often

in Algebra. They are to be considered specially.

These are to be remembered as Formulas in Algebra.

Remembering these formulas in Algebra is as important

as remembering multiplication tables in Arithmetic.

We give a list of these Formulas and Apply

them to solve a Number of problems.

We give Links to other Formulas in Algebra.

Here is the list of Formulas in

Polynomials which are very useful in Algebra.

Formulas in Polynomials :

** Algebra Formula 1 in Polynomials: ** * Square of Sum of Two Terms: *

** (a + b)2 = a2 + 2ab + b2 **

** (a - b)2 = a2 - 2ab + b2 **

** (a + b)(a - b) = a2 - b2 **

** (a + b)(a2 - ab + b2) = a3 + b3 **

** (a - b)3 = a3 - 3a2b + 3ab2 - b3 = a3 - 3ab(a - b) - b3 **

(First term + Second term)2

= (First term)2 + 2(First term)(Second term) + (Second term)2

Jul 02, 2011 | Educational & Reference Software

let's look at **volume.** Consider a volume of a cube that is x on
a side. The volume of the cube is X x Xx X = X3 (with the appropriate
units - meters3 or km3 or cm3 (if you cannot
handle metric))

Mar 30, 2011 | Educational & Reference Software

The surface area of the outer surface is the circumference of the outside of the pipe times its length. So, if OR is the radius of the outside of the pipe and SO is the outer surface area,

SO = 2 * pi * OR * 14

Similarly, the surface area of the outer surface is SI = 2 * pi * IR *14 (if SI is the inner surface area and IR is the radius of the inside of the pipe.

The question states that the difference between the outside surface area and the inside surface area is 88 sq. cm:

SO - SI = 88 ; substituting:

(2 * pi * OR * 14) - (2 * pi * IR * 14) = 88 ; factoring

(2 * pi * 14) (OR - IR) = 88 ;dividing both sides by 2*pi*14

(OR - IR) = 88/(2 * pi) = 88/(2 * 3.14159*14) = 1.00

So, the outside radius is 1 cm more than the inside radius.

It's not clear if the volume stated is the volume of the metal in the pipe or the volume of air inside the pipe, so I will solve it both ways:

If volume of 176cc is of the air inside, the formula for this volume is 14 * pi * IR *IR

176 = 14 * 3.14159 * IR * IR ; dividing both sides by 14 * 3.14159

176/(14 * 3.14159) = IR * IR ; doing the arithmetic

4 = IR * IR ; taking the square root of both sides

sqrt(4) = IR

**IR = 2 cm**

substituting back into the first equation, the OR is 1cm more than the IR, so

**OR = 3 cm**

If volume of 176cc is of the iron in the pipe, the formula for that volume is the difference between the volume of the outside of the pipe and the volume of the inside of the pipe, or

(14 * pi * OR * OR) - (14 * pi * IR * IR) = 176 ; factoring

(14 * pi) ((OR * OR) - (IR * IR)) = 176 ; dividing both sides by 14 * pi

((OR * OR) - (IR * IR)) = 176/(14 * 3.14159) = 4

but, since OR is 1 cm more than IR (from above), we can substitute OR = IR + 1

and OR * OR = (IR + 1) * (IR + 1) = (IR*IR) + 2*IR +1

So, ((OR * OR) - (IR * IR)) = 4 becomes

(IR*IR) + 2*IR +1 - (IR*IR) = 4 ; simplifying (IRsquared - IRsquared = 0)

2*IR + 1 = 4 ; subtract 1 from both sides

2*IR = 3 ; divide both sides by 2

IR = 3/2 ;

**IR = 1.5cm**

**OR = 2.5cm**

SO = 2 * pi * OR * 14

Similarly, the surface area of the outer surface is SI = 2 * pi * IR *14 (if SI is the inner surface area and IR is the radius of the inside of the pipe.

The question states that the difference between the outside surface area and the inside surface area is 88 sq. cm:

SO - SI = 88 ; substituting:

(2 * pi * OR * 14) - (2 * pi * IR * 14) = 88 ; factoring

(2 * pi * 14) (OR - IR) = 88 ;dividing both sides by 2*pi*14

(OR - IR) = 88/(2 * pi) = 88/(2 * 3.14159*14) = 1.00

So, the outside radius is 1 cm more than the inside radius.

It's not clear if the volume stated is the volume of the metal in the pipe or the volume of air inside the pipe, so I will solve it both ways:

If volume of 176cc is of the air inside, the formula for this volume is 14 * pi * IR *IR

176 = 14 * 3.14159 * IR * IR ; dividing both sides by 14 * 3.14159

176/(14 * 3.14159) = IR * IR ; doing the arithmetic

4 = IR * IR ; taking the square root of both sides

sqrt(4) = IR

substituting back into the first equation, the OR is 1cm more than the IR, so

If volume of 176cc is of the iron in the pipe, the formula for that volume is the difference between the volume of the outside of the pipe and the volume of the inside of the pipe, or

(14 * pi * OR * OR) - (14 * pi * IR * IR) = 176 ; factoring

(14 * pi) ((OR * OR) - (IR * IR)) = 176 ; dividing both sides by 14 * pi

((OR * OR) - (IR * IR)) = 176/(14 * 3.14159) = 4

but, since OR is 1 cm more than IR (from above), we can substitute OR = IR + 1

and OR * OR = (IR + 1) * (IR + 1) = (IR*IR) + 2*IR +1

So, ((OR * OR) - (IR * IR)) = 4 becomes

(IR*IR) + 2*IR +1 - (IR*IR) = 4 ; simplifying (IRsquared - IRsquared = 0)

2*IR + 1 = 4 ; subtract 1 from both sides

2*IR = 3 ; divide both sides by 2

IR = 3/2 ;

Jan 11, 2011 | Mathsoft StudyWorks! Mathematics Deluxe...

From the second step the difference between pirate x and pirate x+1 is 5.

1 pirate- 3 men 2 pirates- 8 men 3 pirates - 13 men 4 pirates- 18 men 5 pirates- 23

1 pirate- 3 men 2 pirates- 8 men 3 pirates - 13 men 4 pirates- 18 men 5 pirates- 23

Jun 27, 2010 | Mathsoft StudyWorks! Middle School Deluxe...

find "fx" on your toolbar; choose all formulas find percentage, you can set a specific percentage to the cell, just put the number you want a percentage of or if you want to keep that number, put the percentage formula in the next cell <%a:2>

Apr 16, 2009 | Educational & Reference Software

Hi Dear, there are several solutions

ali_zulfikar@yahoo.com

9899780221

- In ms excel type a fraction formula and in tools--> formula auditing -->
- Please download offcemath.msi for MS Word 2007 from www.office.microsoft.com and install it.

its calculator part will show you the steps of solving fractions in insert--> equations-->maths. - Alternatively you can download microsoft math trial from www.microsoft.com this will show you all steps.

ali_zulfikar@yahoo.com

9899780221

Mar 04, 2009 | Core Learning Fractions Step-By-Step...

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