Question about SoftMath Algebrator - Algebra Homework Solver (689076614429)

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15^2-21x-18 cannot factor, say it has a bug.
I get this a lot. What is the problem

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The exact equation is
15x^2 - 21x - 18
=3(5x^2 - 7x - 6)
=3{5x^2 -(10-3)x -6 }
=3{5x^2 - 10x + 3x -6}
=3{5x(x - 2) + 3(x-2)}
=3(x-2)(5x+3) these are the factors

Thanks

Zulfikar Ali
ali_zulfikar@yahoo.com
9899780221

Posted on Feb 06, 2009

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Ways to find highest common factors?


Do a prime factorization of the two numbers. Use condensed (power) notation for each prime factor.
Example
N1=(2^5)*(3^4)*(7^2)(11^3)
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2 is a factor in N1 and N2, the smallest power of 2 is 4, thus 2^4 is common to N1, and N1. You could write 2^5=2*2^4
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The Rectangular pond at a zoo is 18 m long 12 m wide. The owner of the zoo wants to double the area of the pond by increasing the length and the width by the same amount. By how much should the length and...


The current area of the pond is 18m by 12 m, so, if A is the current area, A=18*12
Twice the area would be 2A and it is to be accomplished by adding the same amount, say x, to both dimensions. In symbols, that is:
2A = (18+x) * (12+x)
But we know A is 18*12, so
2(18*12) = (18+x) * (12+x) ; doing the arithmetic
432 = (18+x) * (12+x) ; doing the multiplication using FOIL (first, outside, inside, last)
432 = 18*12 + 18x +12x + x*x ; simplying
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0 = -216 + 30x + x*x : or
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This has two solutions, 6 and (-36). Since a negative number doesn't make sense in this case, the answer is to add 6m to each side.

Check (18+6) (12+6) = ?
24 * 18 = ?
432 , which is indeed twice the original area of 216 ( = 18*12)

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