Question about SoftMath Algebrator - Algebra Homework Solver (689076614429)

A rectangular window is 57.7 cm by 68.5 cm.what is the perimeter of the window?

Posted on Jan 07, 2009

Let x = the short side. Then the long side is the short side plus 6 meters

now we have 2 sides that are x meters long, add those together gives us 2x for the length

of both short sides

The length of the long side is x + 6 for one side and x + 6 for the other side. Added together we have x + 6 + x + 6 = 2x + 12

Adding the 4 sides together we get 2x ( the 2 short sides) + 2x + 12 (the long sides) we get 4x + 12 = the perimeter or 628. 4x + 12 = 628. Subtract 12 from both sides of the equation leaves 4x = 616. divide both sides by 4 leaves x = 154 So the width is 154 meters and the length is 160 meters.

Hope this helps

Good luck Loringh

Posted on Oct 18, 2008

One dimension is the length lower case **l,** the other is the width **w**. The perimeter for this rectangle is P= **2*l+2*w**=2*(l+w)=2*(7/8 +5/16)

=2*(14/16+5/16)= 2*(19/16)=19/8 inches.

=2*(14/16+5/16)= 2*(19/16)=19/8 inches.

Sep 23, 2014 | Educational & Reference Software

160 by 140

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.

Divide both sides by 2: w+l=300

The length is 20 more than the width: l=w+20

Substituting in the previous equation: w+(w+20)=300

Collecting terms: 2w+20=300

Subtract 20 from both sides: 2w=280

Divide by 2: w=140

Thus the width is 140. Substituting into the equation for length: l=140+20

Simplifying: l=160

The width is 140 and the length is 160

The perimeter is 600, so 2w+2l=600 where w is the width and l is the length.

Divide both sides by 2: w+l=300

The length is 20 more than the width: l=w+20

Substituting in the previous equation: w+(w+20)=300

Collecting terms: 2w+20=300

Subtract 20 from both sides: 2w=280

Divide by 2: w=140

Thus the width is 140. Substituting into the equation for length: l=140+20

Simplifying: l=160

The width is 140 and the length is 160

Sep 15, 2014 | MathAid Algebra II

Say length is x.

Width is x-24.

Perimeter is length plus width plus length plus width = 228.

x + (x-24) + x + (x-24) = 228

4x-48 = 228

4x=276

x=69

length = 69

width = 69-24= 45

check: 45 + 69 + 45 + 69 = 228

Width is x-24.

Perimeter is length plus width plus length plus width = 228.

x + (x-24) + x + (x-24) = 228

4x-48 = 228

4x=276

x=69

length = 69

width = 69-24= 45

check: 45 + 69 + 45 + 69 = 228

Dec 18, 2013 | Educational & Reference Software

Right Rectangular prism, Length L, width W, Height H

Volume=2058 cm^3=L*W*H

However

L=3W, and H=2W

(3W)*W*(2W)=**6 W^3=2058**

W^3=(2058/6)=343

**W**=Cube root of 343=**(343)^(1/3)=7 cm**

**L=3*7=21 cm**

H=2*7=14 cm

Volume=2058 cm^3=L*W*H

However

L=3W, and H=2W

(3W)*W*(2W)=

W^3=(2058/6)=343

H=2*7=14 cm

Oct 29, 2013 | Educational & Reference Software

Rectangle has two pairs of equal sides.

L=length=3 units

w=width =1 unit

**Perimeter = sum of the measures of all sides.**

2 sides with measure L: sum of lengths=**2*L**

2 sides with measure w: sum of widths=**2*w**

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

L=length=3 units

w=width =1 unit

2 sides with measure L: sum of lengths=

2 sides with measure w: sum of widths=

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

Oct 29, 2013 | Mathsoft StudyWorks! Mathematics Deluxe...

Rectangle has two pairs of equal sides.

L=length=3 units

w=width =1 unit

**Perimeter = sum of the measures of all sides.**

2 sides with measure L: sum of lengths=**2*L**

2 sides with measure w: sum of widths=**2*w**

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

L=length=3 units

w=width =1 unit

2 sides with measure L: sum of lengths=

2 sides with measure w: sum of widths=

Perimeter = 2L+2w=2(L+w)=2(1+3)=8 units.

Oct 29, 2013 | Educational & Reference Software

Since the 'base' and 'top' of any prism have the same shape, the surface area can be found by

- surface area of prism = 2 * area of base + perimeter of base * H

- surface area = 2LW + 2(L+W)H
- = 2 * 7 * 4 + 2*(7+4)*5
- = 56 + 2 * 11 * 5
- = 56 +110
- = 166 sq cm

Sep 05, 2011 | Encore Math Advantage Algebra II and...

1. Well this one is pretty simple. Since you are not supposed to trim the length trim the width instead.

to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.

2. let the length of rectangle be x cm

and breadth = 20 cm

now original perimeter = 2(x+20) cm

new length = x-30 cm

breadth remains same = 20 cm

new perimeter = 2(x-30+20) cm = 2(x-10) cm

According to question

new perimeter = old perimeter /2

2(x-10) = 2(x+20) /2

2x -20 = x + 20

x = 40 cm

hence length of longer side 40 cm.

If you want to directly comm ankitsharma.220@gmail.com

to make the perimeter 0.4 m shorter cut the cloth by 0.2 m width the picture will make it clear.

2. let the length of rectangle be x cm

and breadth = 20 cm

now original perimeter = 2(x+20) cm

new length = x-30 cm

breadth remains same = 20 cm

new perimeter = 2(x-30+20) cm = 2(x-10) cm

According to question

new perimeter = old perimeter /2

2(x-10) = 2(x+20) /2

2x -20 = x + 20

x = 40 cm

hence length of longer side 40 cm.

If you want to directly comm ankitsharma.220@gmail.com

Feb 13, 2011 | Vivendi Excel@ Mathematics Study Skills...

Hello

**Rectangular Prism/Cuboid Definition:**

A Rectangular Prism/Cuboid is a solid figure bounded by six rectangular faces, a rectangular box. All angles are right angles, and opposite faces of a cuboid are equal. It is also a right rectangular prism.

**Rectangular Prism/Cuboid Formula**:

Area of Base(A) = l * w

Perimeter of Base(P) = 2l + 2w

Surface Area of Prism = 2(lw) + (2l + 2w)h = 2A + Ph

Volume of Prism = lwh = Ah

Diagonal of Prism = Sqrt(l² + w² + h²)

where

l = length, w = width, h = height

Hope this helps, if so do rate the solution

A Rectangular Prism/Cuboid is a solid figure bounded by six rectangular faces, a rectangular box. All angles are right angles, and opposite faces of a cuboid are equal. It is also a right rectangular prism.

Area of Base(A) = l * w

Perimeter of Base(P) = 2l + 2w

Surface Area of Prism = 2(lw) + (2l + 2w)h = 2A + Ph

Volume of Prism = lwh = Ah

Diagonal of Prism = Sqrt(l² + w² + h²)

where

l = length, w = width, h = height

Hope this helps, if so do rate the solution

Jan 15, 2011 | MathRescue Word Problems Of Algebra Lite

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