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Math algebra like 2x=4 or 6x=12 and what number do i devide both sides by to solver the equation

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Divide the first equation by 2, the second by 6 (i.e. the number that comes before the x)

Posted on Oct 05, 2008

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What is the graph linear equation for y=2*+1


Now is the equation supposed to be y=2x+1? If so,
graph-linear-equation-y-2-1-cds52kcxe0my5labvj2rkild-2-0.gif
The graph of y = 2x+1 is a straight line
When x increases, y increases twice as fast, hence 2x
When x is 0, y is already 1. Hence +1 is also needed
So: y = 2x + 1
Here are some example values:
xy = 2x + 1
-1y = 2 × (-1) + 1 = -1
0y = 2 × 0 + 1 = 1
1y = 2 × 1 + 1 = 3
2y = 2 × 2 + 1 = 5
Check for yourself that those points are part of the line above!

Jan 16, 2015 | SoftMath Algebrator - Algebra Homework...

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How do I solve (3x-2y)2(3xy-3)


First, we will find y in terms of x. We will use the first equation to determine this.
4x+2y=2
We can subtract 4x from both sides:
2y=2-4x
And then divide both sides of the equation by two:
y=1-2x
Since we now have y in terms of x, we can substitute this into our second equation.
-3x-y=-3
-3x-(1-2x)=-3
Then, we can distribute the minus sign
-3x-1+2x=-3
-x-1=-3
Next, we can add 1 to both sides of the equation.


-x=-2
Finally, we divide both sides by negative one to isolate x.
x=2
Now that we have x's value, we can find y's value.
The first thing that we determined is:
y=1-2x
We can substitute in the value of x to this equation.
y=1-2x
plot-formula.mpl?expression=y=1-2%2a2&x=0003
y=1-4
y=-3
Therefore, we now have the values of both variables.
x=2
y=-3

Jan 13, 2015 | SoftMath Algebrator - Algebra Homework...

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5I+5(I-31)=55 how do i solve this


Start by using the distributive property to expand the term 5(I-31)=5*I-5*31=5*I-155.
Rewrite the equation as 5*I+5*I-155=55
Combine the terms with I, this yields 10*I-155=55
Add 155 to both sides of the equation 10*I-155+155=55+155
you now get 10*I=210
Divide both sides of the equation by 10
(10*I)/10=210/10
Cancel the 10's on the left and divide 210 by 10 to get 21
Thus I=21

Basically you use the priority order of operations BEDMAS backwards

Feb 13, 2013 | SoftMath Algebrator - Algebra Homework...

1 Answer

4x - 2x + 1 = 5 + x - 7


1. Combine like terms on the left side of =

4x-2x =2x

New left side is 2x + 1

2. Combine like terms on right side of =

5 - 7 = -2

New right side is x - 2

3. New problem is 2x + 1 = x - 2

4. Now get all x terms on left side of =
and all constants on right side of = by adding the opposites of the corresponding terms as you move them across the =

2x - x = -2 - 1

5. Combine the like terms on each side of the =

Left side: 2x - x = x and Right side: -2 -1 = -3

So x = -3

6. Now check your solution by substituting your answer back in to the original problem.

4(-3) - 2(-3) + 1 = 5 + (-3) -7

7. Now do the arithmatic and hopefully the left and right sides are equal.

-12 + 6 +1 = 5 -3 -7
-5 = -5

Since this is a true statement I know my answer of x = -3 is the correct solution to this problem.

May 17, 2012 | SoftMath Algebrator - Algebra Homework...

1 Answer

Find the radius of the equation x^2+y^2-2x-2y=14


Try casting the equation of the circle into the form (x-h)^2+(y-k)^2=R^2. Here (h,k) would be the center and R the radius.
To do that complete the two squares.
x^2-2x=x^2-2x+1-1=(x^2-2x+1)-1=(x-1)^2 -1.
Do the same for the y terms.
y^2-2y=(y-1)^2 -1.
Substitute these two expressions in your original equation.
(x-1)^2+(y-1)^2 -1-1=14 or (x-1)^2+(y-1)^2=14+2=16
The radius is square root of 16 or 4, and the center is C(1,1).

Sep 20, 2011 | SoftMath Algebrator - Algebra Homework...

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2x^2-19x+22


I'm assumeing the problem is 2x^2 - 19x+22 = 0, solve for x.

I don't see any easy to factor this so I'll either need to complete the square or use the quadratic equation.
Using the quadratic equation, where A = 2, B = -19, and C = 22

x = [-(-19) +/- squareroot( 19^2 - 4*2*22)] / (2*2) =
(19 +/- squareroot(185))/4 =
8.150367 or 1.349632

Feb 01, 2011 | SoftMath Algebrator - Algebra Homework...

1 Answer

Y=7-x x-y=-3


Substitute (7 - X) in for Y in the 2nd equation and you get:

X- (7 - X) = -3 => 2X - 7 = -3 => 2X = 4

Solve this for X and you get X =2.

Plug X = 2 back into the first equation and you get Y = 7 - 2 = 5.

Therefore, the answer is X = 2 and Y = 5

I hope this helps you out.

Jan 27, 2011 | SoftMath Algebrator - Algebra Homework...

1 Answer

X+y=10 x-y=2 use elimination


  • The 1st equation contains a ‘+y’, while the 2nd contains a ‘-y’ term. they will cancel if added together, so we will add the equations to eliminate ‘y’.
  • x-y=2
  • x+y=10
  • so add them together
  • (x-y)+(x+y)=12
  • 2x = 12
  • X= 12/2 = 6
  • subsitutue for
  • 6+y=10
  • y=10-6=4

  • Answer X = 6 and Y = 4

Apr 11, 2010 | SoftMath Algebrator - Algebra Homework...

1 Answer

Linear equation examples


  1. x - 4 = 10
  2. 2x - 4 = 10
  3. 5x - 6 = 3x - 8
  4. img1.gif

  5. img2.gif
  6. 2(3x - 7) + 4 (3 x + 2) = 6 (5 x + 9 ) + 3

  7. img59.gif

Oct 16, 2009 | SoftMath Algebrator - Algebra Homework...

2 Answers

The perimeter of a rectangular field is 628 meters. The length of the field exceeds its width by 6 meters. What is the demensions.


Let x = the short side. Then the long side is the short side plus 6 meters
now we have 2 sides that are x meters long, add those together gives us 2x for the length
of both short sides

The length of the long side is x + 6 for one side and x + 6 for the other side. Added together we have x + 6 + x + 6 = 2x + 12

Adding the 4 sides together we get 2x ( the 2 short sides) + 2x + 12 (the long sides) we get 4x + 12 = the perimeter or 628. 4x + 12 = 628. Subtract 12 from both sides of the equation leaves 4x = 616. divide both sides by 4 leaves x = 154 So the width is 154 meters and the length is 160 meters.

Hope this helps

Good luck Loringh

Oct 06, 2008 | SoftMath Algebrator - Algebra Homework...

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