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Problems about areas

The standard basketball court for college women is twice as long as its wide.the standard basketball court for college men is 4 feet longer,5 feet wider,and 650 square feet greater in area than the womens court.find the dimensions of the men's court.

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Let x = the width of the women's court. Then 2x is the length of the women's court.
the area of the womens court is x times 2x = 2x^2

the length of the mens court is 4 ft longer than the women's or 2x + 4
The width of the men's court is 5 ft wider than the womwn's or x + 5

The are of the mens court is 650 square feet larger that the womens so we have to add 650 to the area of the womens court so the men's and women's will be equal

Now we have area of the women's court = area of the men's court

2x^2 + 650 = (x + 5) (2x + 4) = 2x^2 + 14x + 20

The x^2 cancel out and we are left with 14X + 20 + 650 solving for x we get x = 45

Plugging x back into the length and width equations we get the length is 94 and the width is 50

Hope this helped

Good luck Loringh

Posted on Oct 18, 2008

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