The standard basketball court for college women is twice as long as its wide.the standard basketball court for college men is 4 feet longer,5 feet wider,and 650 square feet greater in area than the womens court.find the dimensions of the men's court.

Let x = the width of the women's court. Then 2x is the length of the women's court.

the area of the womens court is x times 2x = 2x^2

the length of the mens court is 4 ft longer than the women's or 2x + 4

The width of the men's court is 5 ft wider than the womwn's or x + 5

The are of the mens court is 650 square feet larger that the womens so we have to add 650 to the area of the womens court so the men's and women's will be equal

Now we have area of the women's court = area of the men's court

2x^2 + 650 = (x + 5) (2x + 4) = 2x^2 + 14x + 20

The x^2 cancel out and we are left with 14X + 20 + 650 solving for x we get x = 45

Plugging x back into the length and width equations we get the length is 94 and the width is 50

Hope this helped

Good luck Loringh

Posted on Oct 18, 2008

That depends on the data before July 2010.

Nov 02, 2016 | The Educational & Reference Software

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Sep 14, 2016 | Educational & Reference Software

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Aug 18, 2014 | Educational & Reference Software

Let m represent the subscription rate for a man, and w the subscription rate for a woman.

m/w=4/3, or** m=(4/3)w**.

2 men and 5 women paid 460. Thus

**2m+5w=460.**

Substitute**(4/3)w** for **m**, in **2m+5w=460**.

This gives an equation in the unknown w. Solve for w

2(4/3)w +5w=460 or (23/3)w=460.**Answer is w=60**

Use this value in the relation m=(4/3)w to get m=80.

**Check m/w=80/60=4/3**

m/w=4/3, or

2 men and 5 women paid 460. Thus

Substitute

This gives an equation in the unknown w. Solve for w

2(4/3)w +5w=460 or (23/3)w=460.

Use this value in the relation m=(4/3)w to get m=80.

May 09, 2014 | The Learning Company Achieve! Math &...

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Jan 10, 2014 | SoftMath Algebrator - Algebra Homework...

The current area of the pond is 18m by 12 m, so, if A is the current area, A=18*12

Twice the area would be 2A and it is to be accomplished by adding the same amount, say x, to both dimensions. In symbols, that is:

2A = (18+x) * (12+x)

But we know A is 18*12, so

2(18*12) = (18+x) * (12+x) ; doing the arithmetic

432 = (18+x) * (12+x) ; doing the multiplication using FOIL (first, outside, inside, last)

432 = 18*12 + 18x +12x + x*x ; simplying

432 = 216 + 30x + x*x ; or

0 = -216 + 30x + x*x : or

x*x + 30x -216 = 0 ; using the quadratic equation (or factoring)

(x-6) (x+36) = 0

This has two solutions, 6 and (-36). Since a negative number doesn't make sense in this case, the answer is to add 6m to each side.

Check (18+6) (12+6) = ?

24 * 18 = ?

432 , which is indeed twice the original area of 216 ( = 18*12)

Twice the area would be 2A and it is to be accomplished by adding the same amount, say x, to both dimensions. In symbols, that is:

2A = (18+x) * (12+x)

But we know A is 18*12, so

2(18*12) = (18+x) * (12+x) ; doing the arithmetic

432 = (18+x) * (12+x) ; doing the multiplication using FOIL (first, outside, inside, last)

432 = 18*12 + 18x +12x + x*x ; simplying

432 = 216 + 30x + x*x ; or

0 = -216 + 30x + x*x : or

x*x + 30x -216 = 0 ; using the quadratic equation (or factoring)

(x-6) (x+36) = 0

This has two solutions, 6 and (-36). Since a negative number doesn't make sense in this case, the answer is to add 6m to each side.

Check (18+6) (12+6) = ?

24 * 18 = ?

432 , which is indeed twice the original area of 216 ( = 18*12)

Sep 26, 2010 | Vivendi Excel@ Mathematics Study Skills...

use simultaneous equations, with x = # of men and y = # of women:

x + y = 5000 --> convert to x = 5000 - y 1.1x + 1.15y = 5600

1.1 (5000 - y) + 1.15y = 5600 5500 - 1.1y + 1.15y = 5600 .05y = 100 y = 2000 plug y = 2000 into x + y = 5000

therefore x = 3000

x + y = 5000 --> convert to x = 5000 - y 1.1x + 1.15y = 5600

1.1 (5000 - y) + 1.15y = 5600 5500 - 1.1y + 1.15y = 5600 .05y = 100 y = 2000 plug y = 2000 into x + y = 5000

therefore x = 3000

Jul 09, 2010 | Mathsoft StudyWorks! Mathematics Deluxe...

15 men earns 525

1 man raens 525/15

equals to 35

7 women earns 525

1 women earns 75

so 7 men and 13 women earns 7 *35+13*75=245+975=1220

1 man raens 525/15

equals to 35

7 women earns 525

1 women earns 75

so 7 men and 13 women earns 7 *35+13*75=245+975=1220

Dec 11, 2007 | Bagatrix Algebra Solved! 2005 (105101) for...

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