[H+]=10^(-8.19). The - sign is the change sign key. The result is 1.2589x10^(-9)
SOURCE: I just bought a texas instruments TI-30X IIS
if you want to use your calc for this you would have to put it in as the operations to change the mixed to improper fraction i.e. input exactly as "((8*3)+6)*((3*7)+1)=" remember? take denominator times whole number plus numerator and put over denominator to convert from mixed to improper... hope this helps
SOURCE: TI-30x...I am trying to figure out how I use this calculator
Hello,
Entering the keys and number as you write it can be done with enough parenthees to make sure calculator does what we intend it to.
But I would rather use the commutativity propertie of multiplications to same me some extra ().
Step 1
4 [(+/- change sign)][2nd][10 to the x] [ X ]6.1923 [=]
Step2
[x^2][=]
I first calculate the product 6.1928 x 10^-4 then take the square of the result. Because you can never be sure that the calculator takes 6.1923 to power 2 then multiply or multiply 6.1928 x 10^-4 and raise to power 2.
You can force the calculator with an opening parenthesis and a closing one but if you omit the ) and get an error, it may be hard to detect.
Hope it helps.
SOURCE: how do you plot two liner equations on a ti-84?
I use one of the graphing APPS or do through a program. I have a users manual for TI 84 silver Edition that shows you how to archive\ unarchive to run programs here at this site. Usually, I tell people to just forget about the programs and use the simple concepts so, that they could operate their calculator better. But, if you notice in those program are actually more powerful than the programs you get on the web, because I wrote them to be flawless, or I only used programs that I knew would not clash and were very well written. Won't y1=(2/5)x-(11/5) and -3x+8 work?
y1=(2/5)x-(11/5) and -3x+8
SOURCE: How to use antilog?
Hello,
As you well know the pH is the negative of the log in base 10 of the H+/H3O+ ion concentration. If we use [H+] to represent that concentration, then pH=-log[H+].
To obtain the [H+] you need to calculate the antilog. You write the definition in the form log[H+] =-pH and then calculate 10 to the power of each member. The equality remains valid as both members are treated similarly. Thus
10^( log[H+] ) = 10^(-pH)
Since raising 10 to a power is the inverse function of taking the log in base 10, 10^(log(x))=log(10^(x)) = x (they are inverse of one another), you are left with
[H+]=10^(-pH)
Your calculator has a function [10 to x] accessed by pressing the [2nd] function key. To use it you must enter the negative value of the pH, press the [2nd] function key then the [10 to x], then the = key to get the result (concentration)
Exemple: let the pH=5.5, what is the H+ concentration?
With [(-)] being the change sign key, then
[H+]:[ (-) ] 5.5 [2nd][10 to x] [=]
The result is 0.000003162 or 3.16 x 10^(-6)
Hope it helps.
SOURCE: I need to find a manual for my TI-30X IIS
TI has a "Quick Reference Guide" and a "Guide for Teachers" for download at their web site http://education.ti.com/educationportal/sites/US/productDetail/us_ti30x_iis.html?bid=6
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