Question about Panasonic KX-TG1033S Cordless Phone

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My new phone. I have misplaced the instruction *hoe to use answer Ph ? can you help ?

My new phone......I need instruction about using the answer service on my new panasonic phone can you help ?

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  • anneanb Apr 21, 2009

    I have a Panasonic cordless phone that had somehow gotten on Mute and I cannot turn the Mute off. I have misplaced my manual. Can you help me?

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  • 51 Answers

Just get on the internet...and look up your phone's name in specific and enter that and manuel or instrucitons and do that.or click this link... http://www.retrevo.com/samples/Panasonic-Phones-manuals.html and find your model and then you have it! (scroll down on the link)

Posted on Sep 30, 2008

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6ya6ya
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Posted on Jan 02, 2017

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When I go to use the 'log' button on TI 30XA I do not come up with the same answer as in my course book (for the examples) No real instructions on logs in the little instruction book. Have tried...


You calculate the pH with the relation
pH=-log(c) where c is the value of concentration in mol/L.
ex: c[H+]= 3.57x10^(-6)
pH: (-) [LOG] 3.57 [2nd][EE] [(-)] 6 [ ) ]
Here you have 2 change sign key press [(-)]

If you have the pH, and want to calculate the concentration that yields that value of the pH you proceed as follows
c= 10^(-pH)
Ex pH=8.23
c: [2nd][LOG] [(-) 8.23 [)]

General shortcut.
If concentration is of the form c[H+]= 1*10^(-a) where a is an integer between 0 and 14, the pH is equal to the positive value of exponent.

Ex:c[H+]=1x10^(-5) Mol/L then the pH is just the positive value of the exponent, ie 5 because pH=-log(1.x10^-5) =- log1 -log(10^-5)=0 -(-5)=5
Above I use the rule log(axb)=log(a)+log(b) , the rule log(a^b) = b*log(a)and the facts that log(1)=0 and log(10)=1, the last being true if log stands for log in base 10.

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Instruction manual


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Cannot figure out how to use the reverse log on my Staples Textbook display BD-6410 Calculator the pOH is 6.59 I need to use the reverse log to get the answer for the H+ which is the reverse log of 6.59...


Hello,

You should use the equivalence
y=10^(x) is equivalent to x=log(y)

You should not use word that have no meaning. x above is sometimes called antilog, not reverse log.

The relation linkin pH and pOH is as follows
pH+pOH=14, thus pH=14-pOH

Let c[H+] be the concentation (or if you use the hydronium ion, instead of H+ ) c[H3O+] the concentration of hydronium ion)
c[H+]=c[H3O+]=10^(-pH)

pOH= 6.95 thus pH=14-6.95 = 7.05
If pH=7.05 the c[H+]= 10 ^(-7.05) =8.9125E(-8)

pH= 10^ [X to the power] [(-)]7.05
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Mis placed phone can I cancel the number...or


Have you called the phone to see if some one answers. If they answer, offer a reward to get it back.
if not :

Cancell your service with that phone, then get a new phone using the same phone number.
Your phone company will help you transfer to a new phone.

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Hoe do you use logarithm on TI-36X SOLAR?


Basically you first have to put your answer into scientific notation by pressing the 3rd key then the 6 key. The screen display should change to one big zero and two small zeros.

I was workinggon the same problem with a -log of a chemistry problem to get pH and I knew the answer because I calculated it on it TI-85, but we are not allowed to use graphing calulators on the exam (:-((() so I had to figure out how to do it on this one!

For example, I had pH =-log(2.828947x10^4)

On the TI-36X you change to scientific notation using the instructions above. Once the three zeros enter on the screen:
[4]
[-]
[2nd]
[10^x]

1^-04 should appear on screen, then you multiply by 2.828947

[x]
[2][.][828947]
then your screen will show the answer in scientific notation.

2.828947 in big numbers and in small numbers -04
From there you simply press:
[log]
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check this page http://www.fonefunshop.co.uk/Unlocking/sony.htm

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Durabrand phone model 5562 .


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