Question about Panasonic KX-TG1033S Cordless Phone

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My new phone. I have misplaced the instruction *hoe to use answer Ph ? can you help ?

My new phone......I need instruction about using the answer service on my new panasonic phone can you help ?

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  • anneanb Apr 21, 2009

    I have a Panasonic cordless phone that had somehow gotten on Mute and I cannot turn the Mute off. I have misplaced my manual. Can you help me?



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Just get on the internet...and look up your phone's name in specific and enter that and manuel or instrucitons and do that.or click this link... and find your model and then you have it! (scroll down on the link)

Posted on Sep 30, 2008


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Posted on Jan 02, 2017


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When I go to use the 'log' button on TI 30XA I do not come up with the same answer as in my course book (for the examples) No real instructions on logs in the little instruction book. Have tried...

You calculate the pH with the relation
pH=-log(c) where c is the value of concentration in mol/L.
ex: c[H+]= 3.57x10^(-6)
pH: (-) [LOG] 3.57 [2nd][EE] [(-)] 6 [ ) ]
Here you have 2 change sign key press [(-)]

If you have the pH, and want to calculate the concentration that yields that value of the pH you proceed as follows
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General shortcut.
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You should use the equivalence
y=10^(x) is equivalent to x=log(y)

You should not use word that have no meaning. x above is sometimes called antilog, not reverse log.

The relation linkin pH and pOH is as follows
pH+pOH=14, thus pH=14-pOH

Let c[H+] be the concentation (or if you use the hydronium ion, instead of H+ ) c[H3O+] the concentration of hydronium ion)

pOH= 6.95 thus pH=14-6.95 = 7.05
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