Distance 1.00 equal 1 mile

@Jose Zavala "How long light from moon to earth?":
1.28 Seconds.
Distance Earth to moon =
384402 km, 238856 miles, or 384402000 meters.
Speed of light symbol 'c' in vacuo = 300*m/sec
384402000/300000000=1.28.
Radio-waves also travel at c in space, so communication is delayed at least 1.28 s each way.

First translate the various statements of the problem into equations. then try to solve the equations. It won't do much good if I just gave you the answers.

About 26 miles per hour.

If I am reading the tire size right you are dealing with a different width and not circumference. If in fact it is width it want make any difference, however, if it is circumference then if the tire is smaller the transmission is going to have to turn faster to get 50 MPH or any speed. The speed of your car is measured at the back of our transmission. Smaller tires will make the speed-0-meter read fast and larger tires will give you a slow reading. This is the one that will get you in trouble. With a larger tire and you meter reading 50 you might be doing 60 or more. You can figure the speed of any tire on a car just take the circumference of the tire [how many inches it travels in one revolution] and divide it into 5280' for miles then Multiply it by T=time taken to travel distance then figure in the RPM's and drive your self crazy trying to figure it out.
Again as I said if they are the same circumferance then your speed -o- meter will not change.
Col. Dana Gillespie

A Tachymeter helps you estimate the speed you are going.

It uses the basic formula that speed = Distance/time

Here is how to use it: (For the full article see the link below)

To use tachymeter, simply start the chronograph or stopwatch when the object measured passing the starting line. When the object reaches the next mile or kilometer marker, stop the chronograph or stopwatch. The point on the tachymeter scale that adjacent to the second hand of the watch indicating the speed (in miles per hour or kilometers per hour) of object traveling between the two points.

For example, we want to measure the average speed of a vehicle is moving. Start the chronometer or stopwatch function when the car passes the starting line, and stop the timer after the vehicle traveled exactly 1 mile or 1 kilometer. Then look at where the chronometer hand (the second hand of the watch) is pointing to, and get the reading or value of the corresponding number at the tachymeter bezel or dial. Let's say the stopwatch stop at 3 o'clock position, meaning 15 seconds had elapsed for the car to travel 1 mile or 1 kilometer. At 3 o'clock position, the tachymetre value shows that number of 240, which means the average speed of the vehicle was 240 mph or km/h.

Source(s):

http://www.mydigitallife.info/2006/12/10...

At time 'ZERO', the hat was at distance 'ZERO' from the starting-point.
At time 'T', the hat was at distance 'ONE MILE' from the starting point.
The speed of the boat was the MAXIMUM speed of the boat, MINUS the speed of the current.
At time 'T+5', the hat was being carried by the stream-current toward distance 'ZERO'.
At time 'T+10', the hat was at distance 'ZERO', and the boat was at distance 'ZERO'.
The speed of the boat for the most-recent '10' minutes was the MAXIMUM speed, PLUS the speed of the current.

So, calculate the distance travelled at the 'T+5' time:
DISTANCE = VELOCITY1 multiplied by TIME1.
DISTANCE = VELOCITY2 multiplied by TIME2.

where 'VELOCITY1' is the speed travelling AGAINST the current,
and 'VELOCITY2' is the speed travelling WITH the current.

Finish this "homework" assignment on your own.

The first thing to figure out is the amount of time between the trains is 12 minutes. That would mean for train B to pass the station at 9:37 it would have to travel 22 miles in 12 minutes. Because, traveling at 110 miles/hour in 12 minutes the train would have travel 22 miles. Shown below shows the interpolation to come up with 22 miles.


Train A had to traveled 12 minutes so, it would have been 20 miles ahead of the station. Screened below shows the interpolation to equal 20 miles.


Though this calculation of 20 miles isn't necessary for the parametric solution that is being shown. It was very helpful in my solution in successive approximation. This parametric solution's starting point is at 9:37, not 20 miles ahead.

Using successive approximation, when train A traveled 200 miles in 2 hours, and train B was only 2 miles behind train A. At that point the time varibles needed to be broke down to minutes and seconds which gave me a real accurrate answer. Both trains were side by side in 2 hours and 12 minutes, and had traveled 220 miles from the station. You wouldn't believe how far the significant bits needed to be carried out to get such an accurate number. That's what gave me the idea to substitute, and use a parametric solution. In this solution the t (aka. time) is going to be substituted for the y axis. Next, I broke miles/hour down to mile/minute because, I knew the answer was in minutes: 2 hours and 12 minutes.

110/60=1.833333 so, -20+1.833333 t and 100/60=1.6666667 so, 1.6666667 t

Now load the equation:


Now let's look at the solution from the graph. Each line represents a train.


Notice how the two lines are converging. Where the two lines meet is the exact point when the two trains are side by side.


Substituting t (aka. time) for the y axis show that at the point when the trains were side by side equals 132 minutes. Or 2 hours and 12 minutes. The distance traveled x axis=220 mile from the station.

To a point successive approximation would have been messy, and hard to follow. Somethings can only be solved by using graphs, or better solved by using graphs.

If the gears have been INCREASED the speed etc will be less.
Say it's increased by 18%.In theory,at 100mph real speed, the speedo will read 18%less.i.e. 82mph.
If the speedo is driven off the g/box,all this has to be taken into account.
If the speedo is driven off the wheels(and the wheels have not changed at all)All that will happen is the engine revs will have decreased by 18%.
So,To work out the difference.Divide the distance travelled by 100 and then multiply the answer by 82.(82 is the remaining % of the original)
So if 150 miles is divided by 100=1.5
1.5 is multiplied by 82=123 miles.
Hope this helps

12x60=720 meters in one minute the distance traved is 720 meters in one minute so in four minutes the vechilce has travled 720x4 minutes =2880 meters in four minutes.

/* REXX is better than JAVA -- see: http://www.REXXLA.org */

say 'Welcome to the class named DISTANCE'
pull kilometers junk
if kilometers = ' ' then exit
conversion = 0.62137
miles = kilometers * conversion
say kilometers 'Kilometers is' miles 'Miles.'
exit