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Java program I am in a need of a program that takes 3 parameters - folderpath - extensionlist - regular expression search string and finds all the files in the folderpath with the specified extension containing the search string.

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I would use Perl, easier. Maybe even use POP and PUSH on ARGV to pull the forst argument off as directory and last as extension treating all the other entries as search criteria.

#!/usr/bin/perl # # Date: 13/02/2008 # # Author: Adrian Pavone # # This script takes a specified directory with any number of keywords as arguments,
# and then searches all sub directories, for those keywords. It only # returns a match if it finds all keywords in the same file name. # use File::Find; $dir =$ARGV[0];
; @searchTerms = @ARGV; find ( sub { for my $term (@searchTerms) { return unless $_ =~ /\Q$term/i; } print "$File::Find::name\n"; }, $dir);

Posted on Sep 18, 2008

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6ya6ya
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Posted on Jan 02, 2017

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1 Answer

"Stack overflow at line 0"


b> A stack is a section of memory where a program stores its variables, calculations, option states and program parameters. When started, a program is allocated some memory to use for the stack; a stack overflow happens when a program exceeds its allocation. The offending program may attempt to write into adjacent memory sections, causing conflicts with other programs. Stack overflows are common with Java, C++, Perl and other runtime environments, which assist in running programs. A stack overflow at line 0 indicates that the offending program tripped up from the start; however, stack overflows can occur on any line number.

Click "Start," "Control Panel, then "Internet Options." Click on the "Advanced" tab. Check "Disable Script Debugging (IE)" and "Disable Script Debugging (Other)" under the "Browsing" options. Uncheck "Display a notification about every script error." Check "Enable Automatic Crash recovery." Click "OK." Download and install a Java update from the Java website. http://www.java.com/en/download/manual.jsp Download and install a Windows update. Hope this helps.

Dec 24, 2012 | Microsoft Windows XP Professional

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How to connect Bluetooth GPS using mobile phone


<p>Once I explain how Bluetooth GPS receiver to connect from a mobile phone. Bluetooth GPS Receiver is a device that continuously transmits its position (longitude, latitude and speed) using the Bluetooth protocol. If your phone is Bluetooth-enabled phone, you can connect to a Bluetooth GPS receiver to determine its position. To locate, connect to Bluetooth GPS and mobile phone to get the NMEA sentences for location tracking, you can also program a Java (J2ME) for your phone. Your program should do the following tasks: <br /> <p><br /> <p>1. Bluetooth device within the search area. Each time a Bluetooth device is discovered, discovery listener device Discovered trigger procedure. In the search is completed, the trigger listener discovery process inquiry Completed. <br /> <p><br /> <p>2. Get the name Bluetooth. We have a choice to a group list of Bluetooth-friendly name of the devices found to store. We also need a vector to devices found to store. <br /> <p><br /> <p>3. Select Bluetooth GPS receiver from the list of found devices. <br /> <p>4. Find service by the GPS device. Bluetooth GPS Receiver provides an L2CAP service so that the program needs to find this service for GPS url connection string for. <br /> <p><br /> <p>5. Get connection string from the GPS device. Connection string to the URL will have this format Url = "btspp: Address / bluetooth /:" + + L2CAP_UUID "permission = false; encrypt = false"; <br /> <p><br /> <p>6. Sign up and receive sentences from the GPS device. After plugging in the url in step 5, you can open the connection and extract sentences from the connection string. <br />

on Jun 26, 2011 | Cell Phones

2 Answers

What is strings in java?


Handling character strings in Java is supported through two final
classes: Java String and StringBuffer. The String class implements immutable character strings, which are read-only once the string has been created and initialized, whereas the StringBuffer class implements dynamic character strings. All string literals in Java programs, are implemented as instances of String class. Strings in Java are 16-bit Unicode.

Nov 21, 2012 | Sun Java Programming Language (cdj-275)

1 Answer

Please write a java program to print your full name in a single line.


class username {
public static void main(String[] args) {
System.out.println("your name goes here"); // Display the string.
}
}

Jul 07, 2010 | Sun Java Programming Language (cdj-275)

4 Answers

Java is not working


Hello there :
first you are going to want to ensure that your your current version of java is installed correctly and is not corrupted and if it needs to be reinstalled
download the latest java version and reinstall this . www.java.com
this should be able to take care of the problem that you are having ok?
best regards michael

Aug 23, 2009 | ArcMedia JavaScript Source Code 3000 Pro...

1 Answer

I want to read text file which is located in c drive using java code can anybody help me out


import java.io.*;
import java.util.Scanner;

public final class ReadWithScanner { public static void main(String... aArgs) throws FileNotFoundException {
ReadWithScanner parser = new ReadWithScanner("C:\\Temp\\test.txt");
parser.processLineByLine();
log("Done.");
}

/**
* @param aFileName full name of an existing, readable file.
*/

public ReadWithScanner(String aFileName){
fFile = new File(aFileName);
}

/** Template method that calls {@link #processLine(String)}. */
public final void processLineByLine() throws FileNotFoundException {
Scanner scanner = new Scanner(fFile);
try {
//first use a Scanner to get each line
while ( scanner.hasNextLine() ){
processLine( scanner.nextLine() );
}
}
finally {
//ensure the underlying stream is always closed
scanner.close();
}
}

/**
* Overridable method for processing lines in different ways.
*
* <P>This simple default implementation expects simple name-value pairs, separated by an
* '=' sign. Examples of valid input :
* <tt>height = 167cm</tt>
* <tt>mass = 65kg</tt>
* <tt>disposition = "grumpy"</tt>
* <tt>this is the name = this is the value</tt>
*/

protected void processLine(String aLine){
//use a second Scanner to parse the content of each line
Scanner scanner = new Scanner(aLine);
scanner.useDelimiter("=");
if ( scanner.hasNext() ){
String name = scanner.next();
String value = scanner.next();
log("Name is : " + quote(name.trim()) + ", and Value is : " + quote(value.trim()) );
}
else {
log("Empty or invalid line. Unable to process.");
}
//(no need for finally here, since String is source)
scanner.close();
}

// PRIVATE //
private final File fFile;

private static void log(Object aObject){
System.out.println(String.valueOf(aObject));
}

private String quote(String aText){
String QUOTE = "'";
return QUOTE + aText + QUOTE;
}
}

Jun 22, 2009 | Sun Java Programming Language (cdj-275)

1 Answer

Code for method parseInt() in java


parseInt(java.lang.String, int)

This code takes two arguments, a string constructor from the Java language and an integer. Its purpose is to parse (meaning de-construct or disassemble into component parts) one data type into another.

Here is an example of a Java program to specify and print out the dimensions of a rectangle, taken from the page http://www.roseindia.net/java/beginners/entervaluesfromkeyboard.shtml:

class Rectangle{
int length, breadth;
void show(int x, int y){
length = x;
breadth = y;
}
int calculate(){
return(length * breadth);
}
}
public class EnterValuesFromKeyboard{
public static void main(String[] args) {
Rectangle rectangle = new Rectangle();
int a = Integer.parseInt(args[0]);
int b = Integer.parseInt(args[1]);
rectangle.show(a, b);
System.out.println(" you have entered these values : " + a + " and " + b);
int area = rectangle.calculate();
System.out.println(" area of a rectange is : " + area);
}
}

Apr 09, 2009 | Sun Java Programming Language (cdj-275)

2 Answers

Rename a folder in c drive using java code


import java.io.*;

public class RenameFileOrDir{

public static void main(String[] args) throws IOException{
BufferedReader in = new BufferedReader(new InputStreamReader(System.in));
System.out.print("Please enter the file or directory
name which has to be Renamed : ");

String old_name = in.readLine();
File oldfile = new File(old_name);


if(!oldfile.exists())
{

System.out.println("File or directory does not exist.");

System.exit(0);

}

System.out.print("please enter the new file or directory name : ");

String new_name = in.readLine();

File newfile = new File(new_name);

System.out.println("Old File or directory name : "+ oldfile);
System.out.println("New File or directory name : "+ newfile);
boolean Rename = oldfile.renameTo(newfile);

if(!Rename)
{

System.out.println("File or directory does not rename successfully.");

System.exit(0);

}

else {

System.out.println("File or directory rename is successfully.");

}

}

}

Mar 30, 2009 | Sun Java Programming Language (cdj-275)

1 Answer

Java code for adding octal, hexadecimal subtracting binary,


Hello desireejane,


One method is to do the following

  1. Convert the octal, hexadecimal or binary to decimal.
  2. Add or Subtract the decimal normally
  3. Convert the result back to octal, hexadecimal or binary.

  • Convert the octal to decimal:

public static long octalToDecimal(String octal) throws NumberFormatException {
// Initialize result to 0
long res = 0;

// Do not continue on an empty string
if (octal.isEmpty()) {
throw new NumberFormatException("Empty string is not an octal number");
}

// Consider each digit in the string
for (int i = 0; i < octal.length(); i++) {
// Get the nth char from the right (first = 0)
char n = octal.charAt(octal.length() - (i+1));

int f = (int) n - 48;
// Check if it's a valid bit
if (f < 0 || f > 7) {
// And if not, die horribly
throw new NumberFormatException("Not an octal number");
} else {
// Only add the value if it's a 1
res
+= f*Math.round(Math.pow(2.0, (3*i)));
}
}

return res;
}



Mar 24, 2009 | Sun Java Programming Language (cdj-275)

1 Answer

PHP Extract


you have download the file
exemple : php.rar *......
And You can now extract and edit you file
then upload the file in your ftp

Aug 05, 2008 | The PHP Group PHP

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