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Palindrome program in c language - Computers & Internet

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Posted on Dec 03, 2009

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What is the palindrome of 49


palindromic numbers are simply ones that are the same if you right them normally or backwards 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 11, 22, 33, 44, 55, 66, 77, 88, 99, 101, 111, 121, 131, 141, 151, 161, 171, 181, 191, 202, ...

A number is a palindrome or not, 49 is not one.

Sep 14, 2014 | Cars & Trucks

1 Answer

Create a program that asks for a sentence. Your program will then check if the sentence is a palindrome or not.


Palindrome using C#.net

using System;
using System.Collections.Generic;
using System.Text;

namespace ConsoleApplication1
{
class Program
{
static void Main(string[] args)
{
string str=string .Empty ;

Console.WriteLine("Enter a String");

string s = Console.ReadLine();

int i = s.Length;
//we can get the Length of string by using Length Property

for (int j=i -1; j >= 0; j--)
{
str = str + s[j ];
}
if (str == s)
{


Console.WriteLine(s + " is palindrome");


}
else
{
Console.WriteLine(s + " is not a palindeome");
}

Console.WriteLine(str);

Console.Read();


}

Nov 30, 2010 | Computers & Internet

2 Answers

I am also a palindrome.I am greater than the number of days in a year and less than the product of 19 and 20.What number am I?


the answer is between 356 and 380. a palindrome is a word or phrase that reads the same backward as forward. my guess would be 363.

Aug 10, 2010 | Capcom Zack and Wiki Quest for Barbaros'...

1 Answer

18. A palindrome is a string that reads the same


here is a little vbscript sample str=InputBox("Type String To check For palindrome","")
strR=StrReverse(str)
half=Int(Len(str)/2)
If Left(str,half)=Left(strR,half) Then
    MsgBox ("It's a palindrome string")
Else
    MsgBox ("It's not a palindrome string")
End If

Jun 05, 2010 | Computers & Internet

1 Answer

To find palindrome


// String s contains word to check
boolean palindrome = false;//always false until proven otherwise
int i=0;
int len = s.length();
int halflen = (int)len/2;
for (i=0;i<len/2;i++)
if (s.charAt(i)!=s.charAt(len-i-1))
break;
if (i==halflen)
palindrome=true;

Mar 21, 2009 | Sun Java Desktop System

1 Answer

To print palindrome


// String s contains word to check
boolean palindrome = false;//always false until proven otherwise
int i=0;
int len = s.length();
int halflen = (int)len/2;
for (i=0;i<len/2;i++)
if (s.charAt(i)!=s.charAt(len-i-1))
break;
if (i==halflen)
palindrome=true;

Mar 21, 2009 | Intel Computers & Internet

1 Answer

C++ programming


I hope this helps.
#include<stdio.h>
#include<conio.h>
#include<string.h>
void main()


{
clrscr();
char s[100];
int i,j,l,flag;
printf("\n enter a string:");
gets(s);
l = strlen(s);
j= l-1;
for(i=0;i<=j;i++,j--)


{
if(s[i]==s[j])


{
flag=1;
}
else
{ flag=0;
goto sar;
}
}
if(flag==1)


{
printf("\n string is palindrome");
}
else
sar:
printf("\n string is not a palindrome");
getch();
}

Sep 10, 2008 | Computers & Internet

1 Answer

C++


class Tester100
{

public static void main(String[] args)
{
for (int i =100; i<=999; i++)
System.out.println("palindrome"+=((i/100)+""+((i/10)%10)+""+(i%10)+""+((i/10)%10)+""+(i/100)));

}

Mar 21, 2008 | Computers & Internet

1 Answer

Help me javascript just mail me at ramzy_213@yahoo.com thanx


hello there!!!
First things First !
1) download the ultimate JAVA APL. run again.
O S

Feb 19, 2008 | Audio Players & Recorders

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