Question about Belkin (F5D7230-4) Router (587009)

Linear equation 3x-8y=12 5+2x=6

Posted on Jul 05, 2011

Consider the following system of **3 equations in 3 unknowns**:

*x + y = *2**2 x + 3y + z = 4**

- Subtract 2*(Row1) from Row2 and place the result in the second row; subtract Row1 from Row2 and place in the third row. Leave Row1 as is.

- Subtract Row2 from Row3, and place the result in row3. Leave Row1 and Row2 as they are.

Posted on Sep 17, 2008

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Posted on Jan 02, 2017

What you want to do is solve the linear equation 2x=10 to find the value of the unknown x that makes the equality true. Solving an equation usually involves rearranging therms, factors and so on. However your calculator was not designed to handle the solution of equations, no matter how simple they are.

Some Casio scientific calculators can solve some types of equations (polynomials of degree 2 or 3, simultaneous linear equations in up to 3 unknowns). These are the FX-115 ES (Plus) and FX-991 ES (Plus C). Other equivalent models are sold in the world under different names.

Some Casio scientific calculators can solve some types of equations (polynomials of degree 2 or 3, simultaneous linear equations in up to 3 unknowns). These are the FX-115 ES (Plus) and FX-991 ES (Plus C). Other equivalent models are sold in the world under different names.

Oct 16, 2013 | Casio FX350MS Scientific Calculator

Thhe Casio FX-9860G SD can solve a polynomial equation
of degree 2 or 3 with REAL coefficients. If the complex MODE is set to
REAL it will find the real roots. If the complex mode is set to** a+ib**, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).

Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Alternatively, after you create the system of 4 linear equations you can use the matrix utility to find Real(x), Im(x), Real(y) and Im(y) and recompose the x and y.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).

Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Alternatively, after you create the system of 4 linear equations you can use the matrix utility to find Real(x), Im(x), Real(y) and Im(y) and recompose the x and y.

Mar 17, 2012 | Casio FX-9860G Graphic Calculator

The Casio FX-9860G SD can solve a polynomial equation
of degree 2 or 3 with REAL coefficients. If the complex MODE is set to
REAL it will find the real roots. If the complex mode is set to** a+ib**, it will find the real and complex roots.

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).

Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Apparently it will take coefficients that are real, and will give a Ma Error if any coefficient is complex.

Addendum.

The calculator CANNOT solve equations with complex coefficient. YOU can however convert the system of linear equations with ccomplex coefficients ( of the type you show) as a system of 4 linear equations in 4 unknowns; Split x into a real and an imaginary part, split y into a real and an imaginary part. Substitute Real(x)+iIm(x) for variable x in the equations; substitute Real(y)+iIm(y) for y in the two equations; do the algebra. In each of the original equations split the Real and imaginary parts. You should be able to derive 4 linear equations in unknowns Real(x), Im(x), Real(y), and Im(y).

Use the linear equation solver to obtain the solutions. Recompose x=Real(x)+iIm(x), and y=Real(y)+iIm(y)

Mar 17, 2012 | Casio Office Equipment & Supplies

The simultaneous equation solver requires the coefficients to be real. Similarly matrices must have real coefficients.

Your only alternative is to express each of A and B as a real part and imaginary part.

A= x1+iy1

B=x2+iy2.

Substitute x1+iy1 for A in the two equations. Substitute x2+iy2 for B in the two equations. Do the algebra. Gather real parts and gather imaginary parts. Split each original equation into two equations: One equation comes from setting Real Part of left side = real part of right side (1); the other equations comes from setting the imaginary part of left side= imaginary part of right side (here 0).

Do the same procedure for the 2nd original equation.

At the end of the process you will have 4 coupled linear equations in the 4 unknowns (x1,y1,x2,y2).

Then you might want to use the calculator to solve the derived system. Once you have x1,y1,x2,y2 you reconstruct A=x1+iy1, etc.

Your only alternative is to express each of A and B as a real part and imaginary part.

A= x1+iy1

B=x2+iy2.

Substitute x1+iy1 for A in the two equations. Substitute x2+iy2 for B in the two equations. Do the algebra. Gather real parts and gather imaginary parts. Split each original equation into two equations: One equation comes from setting Real Part of left side = real part of right side (1); the other equations comes from setting the imaginary part of left side= imaginary part of right side (here 0).

Do the same procedure for the 2nd original equation.

At the end of the process you will have 4 coupled linear equations in the 4 unknowns (x1,y1,x2,y2).

Then you might want to use the calculator to solve the derived system. Once you have x1,y1,x2,y2 you reconstruct A=x1+iy1, etc.

Aug 29, 2011 | Casio FX-9860G Graphic Calculator

This calculator cannot handle matrices that have anyone dimension larger than 3.

How to solve your problem?

use a computer program devoted to solving linear equations

OR buy another calculator that can handle larger systems of equations (a graphing calculator, maybe).

How to solve your problem?

- Set up the problem by hand (pencil paper): use Cramer's rules. Make use of the calculator to perform the various calculation.

- Sacrifice one equation which you will use to eliminate one variable of the 4 by expressing it in terms of the other three. Do the algebra to obtain a system of 3 equations in three unknowns.
- Use the calculator to find the solutions ( the three variables that are left).
- Use the 4th equation (the one you scacrificed) to obtain the value of the 4th unknown.

use a computer program devoted to solving linear equations

OR buy another calculator that can handle larger systems of equations (a graphing calculator, maybe).

Feb 16, 2011 | Casio FX-115ES Scientific Calculator

Ok, I will tell you how to enter expressions in your calculator, but you will not be able to 'solve' the equation you gave as example because you can only find y in terms of x or find x in terms of y. To solve for x and for y you need a second linear equation. You must have a system of two simultaneous linear equations.

You can enter equations of any type. Read the rest of the post. Keep in mind that if you are using the Solve( function X must be the unknown. If you are using the Table computational mode, X is the independent variable and Y the dependent one.

The variables you have at your disposal in this calculator are

A, B,C,D,X,Y,M. All of them are accessed by pressing the [ALPHA] key before the key near which is written the name of the variable. You will notice that the markings of the symbols accessed with the [ALPHA] key are of the same color as that of the [ALPHA] key.

You will notice also that there are two = signs.

The one at the bottom right executes the command line. By pressing it you find the result of the expression just entered.

The other = sign is marked on the body of the calculator with the same color as the [ALPHA] key. It is located at the top left of the keyboard (excluding the row with SHIFT, MODE, the navigation buttons)

Example to enter X^2-2X-35=0 you proceed as follows.

Direct access physical keys are in [ ],

[ALPHA] (X) [X to power 2] [ - ] [2] [ * ][ALPHA] (X) [ - ] [3][5] [ALPHA] (=) [0]

Usually when you enter such an expression it is with the intention of solving it for X. By default X is taken to be the UNKNOWN. You will be prompted to enter the value assigned to any other letter symbol (Y, A,B,C,D).

So, if you want to use the Solve function, you enter the equation you are dealing with, and before pressing anything else, press [SHIFT] [CALC] and the calculator will ask you a question: "Solve for X?" , and you press the = sign at the bottom right.

Then you will be prompted for any other non-X letter. Once all non-X variables (if any) are given values, the calculator will return with the solution. You will see on the screen L-R= (should be zero if you are lucky).

You can enter equations of any type. Read the rest of the post. Keep in mind that if you are using the Solve( function X must be the unknown. If you are using the Table computational mode, X is the independent variable and Y the dependent one.

The variables you have at your disposal in this calculator are

A, B,C,D,X,Y,M. All of them are accessed by pressing the [ALPHA] key before the key near which is written the name of the variable. You will notice that the markings of the symbols accessed with the [ALPHA] key are of the same color as that of the [ALPHA] key.

You will notice also that there are two = signs.

The one at the bottom right executes the command line. By pressing it you find the result of the expression just entered.

The other = sign is marked on the body of the calculator with the same color as the [ALPHA] key. It is located at the top left of the keyboard (excluding the row with SHIFT, MODE, the navigation buttons)

Example to enter X^2-2X-35=0 you proceed as follows.

Direct access physical keys are in [ ],

[ALPHA] (X) [X to power 2] [ - ] [2] [ * ][ALPHA] (X) [ - ] [3][5] [ALPHA] (=) [0]

Usually when you enter such an expression it is with the intention of solving it for X. By default X is taken to be the UNKNOWN. You will be prompted to enter the value assigned to any other letter symbol (Y, A,B,C,D).

So, if you want to use the Solve function, you enter the equation you are dealing with, and before pressing anything else, press [SHIFT] [CALC] and the calculator will ask you a question: "Solve for X?" , and you press the = sign at the bottom right.

Then you will be prompted for any other non-X letter. Once all non-X variables (if any) are given values, the calculator will return with the solution. You will see on the screen L-R= (should be zero if you are lucky).

Nov 18, 2010 | Casio fx-300ES Calculator

You can use symbols (X,Y,A,B,C,D, and M, =) to create expressions to use
in the SOLV program or to generate a table of values.

To type them you use [ALPHA] followed by the symbol you want. The symbols on the body of the calculator are of the same color as the ALPHA key. The [=] in expressions is different from the general = sign at the bottom of the keypad.

There are also some typical equations already in the calculator: simultaneous linear equation in 2 or 3 unknowns, and polynomial equations of 2nd and 3rd degree. They are accessed under the EQUATion Mode.

To type them you use [ALPHA] followed by the symbol you want. The symbols on the body of the calculator are of the same color as the ALPHA key. The [=] in expressions is different from the general = sign at the bottom of the keypad.

There are also some typical equations already in the calculator: simultaneous linear equation in 2 or 3 unknowns, and polynomial equations of 2nd and 3rd degree. They are accessed under the EQUATion Mode.

Jun 21, 2010 | Casio FX-115ES Scientific Calculator

Hello,

Sorry this calculator cannot solve equations. It does not have the program. It does not know how to do those things. However it can calculate.**Before you can use the calculator you must prepare all yourself. **When you have solved the problem, you ask the calculator to compute the value of what you found.

Let us clean the equation a bit

2(x-4) -5x=-5

Get rid of the parentheses 2(x-4) becomes 2x-2*4=2x-8 .Put that result where it was in equation

2x-8 -5x=-5

Group together the terms that have x in them 2x-5x=-3x

Then

2x-8-5x=-5, becomes -3x-8=-5

You want to isolate the term with x (have it on one side, and the others on the other side) -3x= -5 -(-8)= -5+8 =3.

The equation becomes

-3x=3 Thus**-x=3/3=1 and x=-1.**

**In general you would have obtained x= (some number/some other number) and that is where the calculator would intervene.**

Hope it helps.

Sorry this calculator cannot solve equations. It does not have the program. It does not know how to do those things. However it can calculate.

Let us clean the equation a bit

2(x-4) -5x=-5

Get rid of the parentheses 2(x-4) becomes 2x-2*4=2x-8 .Put that result where it was in equation

2x-8 -5x=-5

Group together the terms that have x in them 2x-5x=-3x

Then

2x-8-5x=-5, becomes -3x-8=-5

You want to isolate the term with x (have it on one side, and the others on the other side) -3x= -5 -(-8)= -5+8 =3.

The equation becomes

-3x=3 Thus

Hope it helps.

Sep 11, 2009 | Texas Instruments TI-30XA Calculator

Hello,

Let us assume you have two simultaneous linear equations :

**a_1*x+ b_1*y+c_1=0**

a_2*x +b_2*y+c_2=0

where a_1, a_2, b_1, b_2, c_1,c_2 are coefficients (numerical or algebraic).

The problem is to obtain the particular values of the unknowns x and y for which the two equations are both satisfied: If you substitute the particular values of x and y you find in any of the two equations you discover that both equalities are true.

A small system of equations like the one above can be solved by some very simple algorithms (elimination, substitution, combination) which can be carried out by hand.

The solution of large systems of linear equations can be sought by making use of the concepts of matrices (plural of matrix), determinants, and certain rules called Cramer's rules.

Due to its repetitive nature, the algorithm ( a well defined, limited sequence of steps) is suitable for a calculating machine (computer or calculator).

Certain calculators have, embedded in their ROM, a program that solves linear systems of simultaneous equations. Usually you are asked to enter the values of the coefficients a_1, etc. in a set order, then you press ENTER or EXE (Casio) . If a solution exits (not all linear systems have solutions) the calculator displays it.

Hope that satisfies your curiosity.

Let us assume you have two simultaneous linear equations :

a_2*x +b_2*y+c_2=0

where a_1, a_2, b_1, b_2, c_1,c_2 are coefficients (numerical or algebraic).

The problem is to obtain the particular values of the unknowns x and y for which the two equations are both satisfied: If you substitute the particular values of x and y you find in any of the two equations you discover that both equalities are true.

A small system of equations like the one above can be solved by some very simple algorithms (elimination, substitution, combination) which can be carried out by hand.

The solution of large systems of linear equations can be sought by making use of the concepts of matrices (plural of matrix), determinants, and certain rules called Cramer's rules.

Due to its repetitive nature, the algorithm ( a well defined, limited sequence of steps) is suitable for a calculating machine (computer or calculator).

Certain calculators have, embedded in their ROM, a program that solves linear systems of simultaneous equations. Usually you are asked to enter the values of the coefficients a_1, etc. in a set order, then you press ENTER or EXE (Casio) . If a solution exits (not all linear systems have solutions) the calculator displays it.

Hope that satisfies your curiosity.

Aug 12, 2009 | Sharp EL-531VB Calculator

Dec 16, 2013 | Belkin (F5D7230-4) Router (587009)

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