Question about Bagatrix Algebra Solved! 2005 (105101) for PC

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English the total income from two investment is $2350. the investment at 9% producers $ 350 more than the investment at 8%. how much is invested at each rate?

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  • bernard78 Sep 13, 2008

    the total income from two investment is $2350. the investment at 9%
    producers $ 350 more than the investment at 8%. how much is invested at
    each rate?

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Let x = the investment return at 8%

Then x + 350 = the investment return at 9%

The investment at 8% + the investment at 9% = $2350 or x + x + 350 = 2350

Solving for x gives x=1000 Return at 8% was $1000 Return at 9% was %1350

Investment at 8% is formulated as follows. Y = (Initial investment) (.08) = $1000
.08Y = $1000 Y=$12,500 Using the same process for the 9% investment yields an initial investment of $15,000

Initial Investment at 8% = $12,500

Initial Investment at 9% = =$15,000


Hope this helps Good Luck Loringh

Posted on Oct 19, 2008

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What's difference between accounts and finance


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I have a starting amount of $2,125. I invest some of it in a bank that pays 4% a year and some in another back that pays 5% a year. After one year I have earned $100. How much money did I invest in ea


There are 2 values for interest, say R and r, and R = 0.05, r = 0.04

There are 2 values for the amount earned, from the 2 banks, say I and i, and we know I + i = 100

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So then I = P * 0.05 * 1 and
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Pls i need equation for :- The sum of N1200 is invested in three project X,Y,Z at the ratio of 4,5,6 respectively. The expected cash inflow per annum is N700. the combined income for projects X and Y is...


Two ways to get to the same answer:
1) If X,Y, & Z are invested in the ratio of 4:5:6 then the amount invested in Z is 6/(4+5+6) times the total of N1200
= 6/15 * 1200
= N480
(Note: X is 4/15 and Y is 5/15 of the total investment,
4/15 + 5/15 + 6/15 = 15/15)
2) The second sentence says: Income from X plus income from Y minus income from Z is N140 and total income is N700. Total income is 700/1200 of the investment.
As formulas:
(Inc X + Inc Y) - Inc Z = 140 (rewriting: Inc X + Inc Y = 140 + Inc Z)
Inc X + Inc Y + Inc Z = 700
Substituting second formula into third:
(140 + Inc Z) + Inc Z = 700
140 + 2 Inc Z = 700
2Inc Z = 700 - 140 = 560
Inc Z = N280
Inc Z is also 700/1200 of investment in Z.
N280 = 700/1200 investment in Z
Investment in Z is 1200/700 * N280
Investment in Z is N480.

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From my previous solution:
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