sinx+cosx=5, tanx+secx=3 then sinx=? sinx+cosx=5,tanx+secx=3 sinx=? tanx= sinx/cosx, secx=1/cosx 1+sinx/cosx=3 1+sinx=3cosx---------->1 cosx=5-sinx------------->2 sub 2 in 1 1+sinx=3(5-sinx) 1+sinx=15
wat is the solution for sinx-cosx=2 ? whats the appropriate unit of measure for -5 1/4in - 2 2/3 in (sinx+cosx)^2 + (sinx-cosx)^2
does (sinx)^6 + (cosx)^6 = 1 ? like sinx^2 + cosx^2 = 1? no the answer is not equal to 1
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...sinx/1+cosx to solve for the value of tan45 degrees solve for tan45 degrees using the identity tan(x/2)=sinx/1+cosx tan(x/2)=sin(x)/(1+cos(x)) Setting x/2=45, means that x=90 (degrees) But cos(90)=0 ...
(sin-cos)(sin+cos) help!! (sinX-cosX)(sinX+cosX) =(sin^2 - Cos^2X) =Sin^2X - (1-Sin^2X) =Sin^2X -1 + Sin^2X =2Sin^2X -1 Zulfikar Ali [email protected] 9899780221
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