First part: start from rest, this means V0=0, d0=0
The motion equation
d=(1/2)*a*t^2+V0*t+d0
simplifies to
d=(1/2)*a*t^2
With d=0.25 mile or 0.25x1600m or 400m (because 1 mile=1600m) and t=19.9s
d=(1/2)*a*t^2
or
a=2*d/t^2
a=2*400/19.9^2
a=2 m/s2
Second part: Come to a stop.
For constant acceleration from start or decelaration to stop, use this formula
v^2=2*a*d
or
a=v^2/(2*d)
a>0 for acceleration and a
Substituting v=60 mi/h or 60*1600/3600 m/s or 26.67 m/s (because 1 mile=1600m and 1hour=3600 sec)
and d=146 ft or 146/3.3 m or 44.24m (because 1 foot = 1/3.3 m),
we have
a=-26.67^2/(2*44.24)
a=-8 m/s2 (deceleration, a
Because v=at, the time it will take to stop is
t=v/a
t=44.24/8
t=5.5 s.
If you need further help, reach me via phone at
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Nope.no fault codes.everything of throttle body cleaned and check.but sometimes it runs perfectly fine.it happens once in awhile.and sometimes high speed also will happen
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