Question about 1982 Honda CX 500 B
Tried all kinds of methods, from Chemical metal to lead flashing.
There should be an asbestos seal between both - has it gone missing?
Posted on Jun 15, 2009
Hi ..... Have you tried exhaust putty from a motor factors, you may have to take apart and smear over both parts as you assemble, it hardens as the exhaust warms. Good Luck.
Posted on Dec 21, 2008
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Posted on Jan 02, 2017
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The calculated moles of C = [grams C] / [MW of C] = [188 g C / 12.0 g] = 15.7 mol C
Therefore, there are 15.7 moles of O2, as calculated from use of the math expression (with boxes) shown above.
The wanted GRAMS of O2 are calculated from MW of O2 times its number of moles, as follows:
Grams of O2 = 32.0 g O2 x 15.7 mol O2 = 502 grams O2.
For your convenience as you make conversions among grams and moles, you may use the following memory aid:
To go from moles to grams, just notice that moles are beside MW, so multiplying them will give grams (moles x MW = grams). If you want to go from grams to moles, notice that grams are over MW, so (grams/MW) = moles. If you should want to calculate MW, you would divide grams by moles, (grams/moles) = MW.
One more tip: When doing calculations, use at least the same number of significant figures (sig figs) in the molecular weights (and atomic weights) as is in the given numerical data. That is, since there are three sig figs in 188 grams of C, use 12.0 as the atomic weight of C, and 44.0 as the MW of CO2. You would obtain the same answer using 12 and 44, but as you may know, following this rule would be more important in other problems in which the digit past the decimal is not zero. This allows proper rounding off of the final calculated quantity.
Suggestion: Try out this method to other problems involving a chemical reaction. Good luck!
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