Question about Cars & Trucks
You have to check on the ac fuse if it has failed youhave to check on the wiring system
Posted on Oct 19, 2013
Save hours of searching online or wasting money on unnecessary repairs by talking to a 6YA Expert who can help you resolve this issue over the phone in a minute or two.
Best thing about this new service is that you are never placed on hold and get to talk to real repairmen in the US.
Here's a link to this great service
Posted on Jan 02, 2017
your coolant temp sensor on the engine block is probably faulty, however, keep in mind that if it really isn't all that hot outside they may not need to turn on. Once you activate the A/C the fans come on automatically since they have to cool the condensor...
If your car is not overheating do not worry about it.
Posted on Aug 29, 2008
As long as the fan eventually shuts off this isn't a problem,the fan will continue to run for a bit after the car is turned off,once it reaches a set temprature it will turn off.
Posted on May 02, 2009
You must of lost freon and when there is no freon your clutch will not activate.Must check it for pressure in the lines.If there is pressure check pressure switch.Good luck let me know
Posted on May 24, 2009
either the freon charge is about 1/3 low, or the expansion valve needs to be replaced. Freon is getting into the evaporator, but not in great enough volume to cool the air unless it is coming in cool to start with. check your ac charge, and if it is full, then have it emptied, change out the expansion valve, and recharge it
Posted on Sep 04, 2009
Tips for a great answer:
May 31, 2018 | Cars & Trucks
Jun 02, 2017 | Dodge Cars & Trucks
Feb 15, 2016 | Cars & Trucks
Apr 08, 2013 | Cars & Trucks
Nov 10, 2017 | 1997 Volkswagen Jetta
Jul 29, 2011 | Plymouth Voyager Cars & Trucks
Oct 02, 2010 | 2005 Saturn VUE
Aug 20, 2010 | 2000 Chevrolet Cavalier
May 07, 2010 | 1999 Ford Expedition
Apr 25, 2009 | Hyundai Motor 2000 Tiburon
15 people viewed this question
Usually answered in minutes!
Step 2: Please assign your manual to a product: